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Alexeev081 [22]
3 years ago
5

Find an equation of the tangent line to the curve xey + yex = 5

Mathematics
1 answer:
Harman [31]3 years ago
8 0
I got:

<span>y′=(−y<span>e^−x</span>−e^y)/xe^y+e^x</span>
then plugged in x and y and got slope of (-5-e^5)
and ended with equation of y=(-5-e^5)x+5

I'm not sure with my solution though i hope this might help you.

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!
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The double number line shows that 4 pounds of tomatoes cost $14. How much does it cost for 1 pound of tomatoes
Anton [14]

Answer:

3.5

Step-by-step explanation:

You would do 14 divided by 4.

1pound =3.5

4 0
3 years ago
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What is the equation for the line of reflection that maps the trapezoid onto itself? Enter your answer in the box______
nadezda [96]
Y = -1

It is an isosceles trapezoid, which is just as well, otherwise it could not reflect onto itself. The line of reflection is the same as the mirror line which is the same as the axis of symmetry.

It runs horizontally exactly through the middle of the shape.

All horizontal lines have the equation y = a value

In this case the line is <span>y=−<span>1</span></span>

6 0
3 years ago
Find a compact form for generating functions of the sequence 1, 8,27,... , k^3
pantera1 [17]

This sequence has generating function

F(x)=\displaystyle\sum_{k\ge0}k^3x^k

(if we include k=0 for a moment)

Recall that for |x|, we have

\displaystyle\frac1{1-x}=\sum_{k\ge0}x^k

Take the derivative to get

\displaystyle\frac1{(1-x)^2}=\sum_{k\ge0}kx^{k-1}=\frac1x\sum_{k\ge0}kx^k

\implies\dfrac x{(1-x)^2}=\displaystyle\sum_{k\ge0}kx^k

Take the derivative again:

\displaystyle\frac{(1-x)^2+2x(1-x)}{(1-x)^4}=\sum_{k\ge0}k^2x^{k-1}=\frac1x\sum_{k\ge0}k^2x^k

\implies\displaystyle\frac{x+x^2}{(1-x)^3}=\sum_{k\ge0}k^2x^k

Take the derivative one more time:

\displaystyle\frac{(1+2x)(1-x)^3+3(x+x^2)(1-x)^2}{(1-x)^6}=\sum_{k\ge0}k^3x^{k-1}=\frac1x\sum_{k\ge0}k^3x^k

\implies\displaystyle\frac{x+4x^3+x^3}{(1-x)^4}=\sum_{k\ge0}k^3x^k

so we have

\boxed{F(x)=\dfrac{x+4x^3+x^3}{(1-x)^4}}

5 0
3 years ago
Find the difference. write the difference in lower term 8 ⅓-5
sergejj [24]

Given data:

The given expression is 8 ⅓-5.

The given expression can be written as,

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Thus, the difference of the given expression is 10/3.

5 0
1 year ago
Find the inverse of the function. f(x) = x+4/3
vodomira [7]
Is there  multip answers

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