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3 years ago

Find an equation of the tangent line to the curve xey + yex = 5

1 answer:

8 0

I got:

y′=(−ye^−x−e^y)/xe^y+e^x
then plugged in x and y and got slope of (-5-e^5)
and ended with equation of y=(-5-e^5)x+5

I'm not sure with my solution though i hope this might help you.

I hope my answer has come to your help. Have a nice day ahead and may God bless you always!

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A group of friends were working on a student film. They spent all their budget on

Sophie [7]

Answer:

$820

Step-by-step explanation:

Total = Equipment + Props

T = 369 + 0.55T

0.45T = 369

T = 820

I hope this helps!

4 0

2 years ago

Miss Davis buys a loaf of bread for $4.25 and sevreal cans of soup for $1.50 each Miss Lee Buys Loaf of bread for the same cost

lina2011 [118]

Answer:

y= x less than 1.5 +4.25

Step-by-step explanation:

5 0

4 years ago

I NEED HELP...finding the slope-intercept form equation

Simora [160]

Answer: y=-13/12x-7

Step-by-step explanation:

To find the slope-intercept form, we first need to find the slope. To find the slope, you use the formula $m=\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$ . We use the two given points to find the slope.

$m=\frac{32-6}{-36-(-12)} =\frac{26}{-24} =-\frac{13}{12}$

Now that we have our slope, we can start filling out the slope-intercept form equation.

y=mx+b

y=-13/12x+b

Since we don't know the y-intercept, we can use one of the given points and solve for b.

6=(-13/12)(-12)+b [multiply (-13/12) and -12]

6=13+b [subtract both sides by 13]

b=-7

With the y-intercept, we can complete our equation.

y=-13/12x-7

4 0

3 years ago

What is the slope of the line?

3241004551 [841]

Answer:

-4/5

Step-by-step explanation:

Two points that I see are not decimals are (-3,1) and (2,-3)

y1-y2/x1-x2= slope

-3-1/2-(-3)= -4/5

5 0

3 years ago

If K = {(x, y)|x - y = 5}, find the corresponding range of y for the domain {0, 2, 4}. {-5, -3, -1} {0, 2, 4} {5, 7, 9}

Aleks04 [339]

Answer:

The range = {-5 , -3 , -1} ⇒ first answer

Step-by-step explanation:

* In any equation the values of x are the domain of it and

the values of y are the range of it

* So to find the range of any equation substitute the values

of x (domain) in the equation to get the corresponding

values of y (range)

* In the problem

∵ K = {(x , y): x - y = 5}

∵ The domain is {0 , 2 , 4}

* Lets find K(0) , K(2) , K(4)

∵ K(0) = (0) - y = 5

∴ -y = 5 ⇒ Multiply both sides by -1

∴ y = -5

∵ K(2) = (2) - y = 5

∴ 2 - y = 5 ⇒ subtract 2 from both sides

∴ -y = 3 ⇒ Multiply both sides by -1

∴ y = -3

∵ K(4) = (4) - y = 5

∴ 4 - y = 5 ⇒ subtract 4 from both sides

∴ -y = 1 ⇒ Multiply both sides by -1

∴ y = -1

* The range = {-5 , -3 , -1}

8 0

3 years ago

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