The player would have reached first base 35 times
Answer:
Step-by-step explanation:
4. h(x) = 2x^2 + 14x - 60
Step-by-step explanation:
Given that h(x) is a quadratic.
Also, h(3) = h(-10) = 0
(A) h(x) = x^2 - 13x - 30
=> h(3) = 3^2 - 13(3) - 30
=> h(3) = 9 - 39 - 30
=> h(3) = -30 - 30
=> h(3) = -60
=> h(3) ≠ 0
(B) h(x) = x^2 - 7x - 30
=> h(3) = 3^2 - 7(3) - 30
=> h(3) = 9 - 21 - 30
=> h(3) = -12 - 30
=> h(3) = -42
=> h(3) ≠ 0
(C) h(x) = 2x^2 + 26x - 60
=> h(3) = 2(3^2) + 26(3) - 60
=> h(3) = 2(9) + 78 - 60
=> h(3) = 18 + 78 - 60
=> h(3) = 96 - 60
=> h(3) = 36
=> h(3) ≠ 0
(D) h(x) = 2x^2 + 14x - 60
=> h(3) = 2(3^2) + 14(3) - 60
=> h(3) = 2(9) + 42 - 60
=> h(3) = 18 + 42 - 60
=> h(3) = 60 - 60
=> h(3) = 0
And
=> h(-10) = 2(-10)^2 + 14(-10) - 60
=> h(-10) = 2(100) - 140 - 60
=> h(-10) = 200 - 200
=> h(-10) = 0
Clearly we have,
=> h(3) = h(-10) = 0
Hence, the correct option is (D) h(x) = 2x^2 + 14x - 60
Answer:
2(3x+4y)
Step-by-step explanation:
2 doubles it
<h2>
Explanation:</h2>
Here we have the following expression:
So we need to simplify that radical expression. By property of radicals we know that:
![\sqrt[n]{a}\sqrt[n]{b}=\sqrt[n]{ab}](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%7D%5Csqrt%5Bn%5D%7Bb%7D%3D%5Csqrt%5Bn%5D%7Bab%7D)
So:
The prime factorization of 22968 is:
Hence:
By property:
![\sqrt[n]{a^n}=a](https://tex.z-dn.net/?f=%5Csqrt%5Bn%5D%7Ba%5En%7D%3Da)
So:
Finally:
<h2>Learn more:</h2>
Radical expressions: brainly.com/question/13452541
#LearnWithBrainly
