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3 years ago

9

ASAP. Look at the picture. Answer choices are: A) the spring has no stretch when a force of 1 pound is applied. B) the spring st

retches a distance of 1 inch when a force of 0.73 pound is applied. C) the spring requires a force of 0.73 pound to stretch 0.73 inch. D) the spring has a length of 1 inch when no force is applied. E) the spring will stretch 1 inch for every pound of force applied. Please only answer if you are 100% correct. Have to get a good grade. Will Mark Brainliest

1 answer:

Katyanochek1 [597]3 years ago

3 0

Answer:

D) the spring has a length of 1 inch when no force is applied

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-2x+5 < 3<br>Someone explain it and solve pls

Artist 52 [7]

Answer:

-2x+5<3

-2x<5-3

-2x<2

-2x>2

Divide de both sides by -2

x>-1

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3 years ago

If it takes 4 gallons of gas to go 92 miles, how many can be driven in 6 gallons

saveliy_v [14]

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2 years ago

Find sin2x, cos2x, and tan2x if sinx=-15/17 and x terminates in quadrant III

vodka [1.7K]

Given:

$\sin x=-\dfrac{15}{17}$

x lies in the III quadrant.

To find:

The values of $\sin 2x, \cos 2x, \tan 2x$ .

Solution:

It is given that x lies in the III quadrant. It means only tan and cot are positive and others are negative.

We know that,

$\sin^2 x+\cos^2 x=1$

$(-\dfrac{15}{17})^2+\cos^2 x=1$

$\cos^2 x=1-\dfrac{225}{289}$

$\cos x=\pm\sqrt{\dfrac{289-225}{289}}$

x lies in the III quadrant. So,

$\cos x=-\sqrt{\dfrac{64}{289}}$

$\cos x=-\dfrac{8}{17}$

Now,

$\sin 2x=2\sin x\cos x$

$\sin 2x=2\times (-\dfrac{15}{17})\times (-\dfrac{8}{17})$

$\sin 2x=-\dfrac{240}{289}$

And,

$\cos 2x=1-2\sin^2x$

$\cos 2x=1-2(-\dfrac{15}{17})^2$

$\cos 2x=1-2(\dfrac{225}{289})$

$\cos 2x=\dfrac{289-450}{289}$

$\cos 2x=-\dfrac{161}{289}$

We know that,

$\tan 2x=\dfrac{\sin 2x}{\cos 2x}$

$\tan 2x=\dfrac{-\dfrac{240}{289}}{-\dfrac{161}{289}}$

$\tan 2x=\dfrac{240}{161}$

Therefore, the required values are $\sin 2x=-\dfrac{240}{289},\cos 2x=-\dfrac{161}{289},\tan 2x=\dfrac{240}{161}$ .

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2 years ago

The diagram shows a sector of a circle radius 10cm

Yuki888 [10]

Answer:

$\text{Perimeter of sector = 43.6 (Rounded to the nearest tenth.)}$

Step-by-step explanation:

$\text{Perimeter of the sector = Radius + arc length + radius}$

$\text{Radius = 10 cm}$

$\text{Perimeter of the sector = 10 + arc length + 10 }$

$\text{Perimeter of the sector = 20 + arc length }$

$\text{arc length = (sector angle/ 360 ) * perimeter of the circle}$

$\text{Perimeter of a circle }=2\pi r$

$\text{sector angle} = 135$

$\text{arc length} = (135/ 360 ) * 2\pi (10)$

$= (3/8) 20\pi$

$= 15\pi /2$

$\text{Using }\pi =3.14$

$= 15 * 3.14 /2$

$= 23.55$

$\text{Perimeter of the sector = 20 + 23.55}$

$= 43.55$

$= 43.6 cm$

$\text{perimeter of the sector = 43.6 cm }$

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2 years ago

hodyreva [135]

Tip: Go to the internet and put the topic you are focused more on that you posted in Brainly

Step-by-step explanation:

Try it to give you some help

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2 years ago