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igomit [66]
2 years ago
15

URGENT

Mathematics
1 answer:
AlekseyPX2 years ago
5 0

Answer:

hope you can understand

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PLEASE HELP THANK YOU IN ADVANCE NEED TO SUBMIT SOON!! PLEASE PLEASE PLEASE HELP
Serjik [45]
Provate school in 2005
f(t)=85+18t

public school
g(t)=95+15t

graph
easy
replace g(t) and f(t) with y
y=18t+85
y=15t+95
input values for t and get values for y

y=18t+85
when t=0 y=85
when t=1 y=103
plot the oints (0,85) and (1,103)

y=15t+95
if t=0 then y=95
if t=1 then y=110
plot the points (0,95) and (1,110)

the easier way would just to be to solve the equatons but anyway
interscection point is (3 and 1/3,145)

so after 3 years (2008) it is about 145
6 0
3 years ago
What is the solution to -122 < -3(-2-8x) -8x
Mariulka [41]

Answer:

x>-8

Step-by-step explanation:

-122<-3(-2-8x)-8x

-122<6+24x-8x

-128<16x

x>-8

5 0
3 years ago
Find equation where line passes through (7,8) and perpendicular to line y=8
forsale [732]
Since in y=8, the slope is 0 (because there is no x) and b is 8 in y=mx+b, we know that the perpendicular line is x=(something) because the perpendicular lines of y=<number> are x=<number> due to that y=<number> equations are strictly horizontal while x=<number> equations are strictly vertical. Since we know that x=<number> has to pass through (7, 8), x =7
5 0
2 years ago
A pipe consists of two concentric cylinders, with the inner cylinder hollowed out. Describe how you could calculate the volume o
elena-14-01-66 [18.8K]

Answer:

cylinder formula

Step-by-step explanation:

4 0
3 years ago
The number of bacteria in a refrigerated food product is given by N ( T ) = 27 T 2 − 180 T + 100 N(T)=27T2-180T+100, 7 &lt; T &l
NeX [460]

Answer:

N(T(t))=432t^2-374.4t-118.88

The number of Bactria after 5.8 hours is 12242.

Step-by-step explanation:

The number of bacteria in a refrigerated food product is given by

N(T)=27T^2-180T+100

where, T is the temperature of the food.

When the food is removed from the refrigerator, then the temperature is given by

T(t)=4t+1.6

We need to find the composite function N(T(t)).

N(T(t))=N(4t+1.6)

N(T(t))=27(4t+1.6)^2-180(4t+1.6)+100

N(T(t))=432t^2+345.6t+69.12-720t-288+100

N(T(t))=432t^2-374.4t-118.88

where N(T(t)) is the number of bacteria after t hours.

Substitute t=5.8 in the above function.

N(T(5.8))=432(5.8)^2-374.4(5.8)-118.88

N(T(5.8))=14532.48-2290.4

N(T(5.8))=12242.08

N(T(5.8))\approx 12242

Therefore, the number of Bactria after 5.8 hours is 12242.

7 0
3 years ago
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