Question

How do we solve this? (No need to find x)

Answer 1

Answer:

Hi,

Step-by-step explanation:

We can't solve that but reduce it to the same denominator.

$\dfrac{x+5}{x}+\dfrac{x+8}{x-1}\\\\=\dfrac{(x+5)(x-1)+x(x+8)}{x(x-1)}\\\\=\dfrac{x^2+5x-x-5+x^2+8x}{x(x-1)}\\\\=\dfrac{2x^2+12x-5}{x(x-1)}$