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34kurt
2 years ago
7

Elevator 1 in a building moved from ground position to a final position of +16 feet. Elevator 2 in the same building moved from

ground to a final position of -25 feet. Wich statement best describes the final positions of these two elevators?
Elevator 1 is 16 feet below ground level, and elevator 2 is 25 feet above ground level

Elevator 1 is 16 feet above ground level, and elevator 2 is 25 feet below ground level

Elevator 1 is 16 feet above ground level, and elevator 2 is 25 feet below the position of elevator 1

Elevator 1 is 16 feet below ground level, and elevator 2 is 25 feet above the position of elevator 1.​
Mathematics
1 answer:
lilavasa [31]2 years ago
8 0
928282827282828382082820ks
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Determine if true:<br> 3^3x4=108
AlekseyPX

Answer:

<u>True</u>

Step-by-step explanation:

3³ x 4

= 3 x 3 x 3 x 4

= 9 x 12

= 108

<u>True</u>

8 0
2 years ago
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I need the answer for this asp.
TEA [102]

Answer:

This is Isosceles Right

Step-by-step explanation:

An Isosceles is a triangle that has two sides the same length and one side longer or shorter

An Right is an triangle with a 90˚

Hope this helps!

3 0
2 years ago
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Find all the complex roots. Write the answer in exponential form.
dezoksy [38]

We have to calculate the fourth roots of this complex number:

z=9+9\sqrt[]{3}i

We start by writing this number in exponential form:

\begin{gathered} r=\sqrt[]{9^2+(9\sqrt[]{3})^2} \\ r=\sqrt[]{81+81\cdot3} \\ r=\sqrt[]{81+243} \\ r=\sqrt[]{324} \\ r=18 \end{gathered}\theta=\arctan (\frac{9\sqrt[]{3}}{9})=\arctan (\sqrt[]{3})=\frac{\pi}{3}

Then, the exponential form is:

z=18e^{\frac{\pi}{3}i}

The formula for the roots of a complex number can be written (in polar form) as:

z^{\frac{1}{n}}=r^{\frac{1}{n}}\cdot\lbrack\cos (\frac{\theta+2\pi k}{n})+i\cdot\sin (\frac{\theta+2\pi k}{n})\rbrack\text{ for }k=0,1,\ldots,n-1

Then, for a fourth root, we will have n = 4 and k = 0, 1, 2 and 3.

To simplify the calculations, we start by calculating the fourth root of r:

r^{\frac{1}{4}}=18^{\frac{1}{4}}=\sqrt[4]{18}

<em>NOTE: It can not be simplified anymore, so we will leave it like this.</em>

Then, we calculate the arguments of the trigonometric functions:

\frac{\theta+2\pi k}{n}=\frac{\frac{\pi}{2}+2\pi k}{4}=\frac{\pi}{8}+\frac{\pi}{2}k=\pi(\frac{1}{8}+\frac{k}{2})

We can now calculate for each value of k:

\begin{gathered} k=0\colon \\ z_0=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{0}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{0}{2}))) \\ z_0=\sqrt[4]{18}\cdot(\cos (\frac{\pi}{8})+i\cdot\sin (\frac{\pi}{8}) \\ z_0=\sqrt[4]{18}\cdot e^{i\frac{\pi}{8}} \end{gathered}\begin{gathered} k=1\colon \\ z_1=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{1}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{1}{2}))) \\ z_1=\sqrt[4]{18}\cdot(\cos (\frac{5\pi}{8})+i\cdot\sin (\frac{5\pi}{8})) \\ z_1=\sqrt[4]{18}e^{i\frac{5\pi}{8}} \end{gathered}\begin{gathered} k=2\colon \\ z_2=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{2}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{2}{2}))) \\ z_2=\sqrt[4]{18}\cdot(\cos (\frac{9\pi}{8})+i\cdot\sin (\frac{9\pi}{8})) \\ z_2=\sqrt[4]{18}e^{i\frac{9\pi}{8}} \end{gathered}\begin{gathered} k=3\colon \\ z_3=\sqrt[4]{18}\cdot(\cos (\pi(\frac{1}{8}+\frac{3}{2}))+i\cdot\sin (\pi(\frac{1}{8}+\frac{3}{2}))) \\ z_3=\sqrt[4]{18}\cdot(\cos (\frac{13\pi}{8})+i\cdot\sin (\frac{13\pi}{8})) \\ z_3=\sqrt[4]{18}e^{i\frac{13\pi}{8}} \end{gathered}

Answer:

The four roots in exponential form are

z0 = 18^(1/4)*e^(i*π/8)

z1 = 18^(1/4)*e^(i*5π/8)

z2 = 18^(1/4)*e^(i*9π/8)

z3 = 18^(1/4)*e^(i*13π/8)

5 0
1 year ago
The mapping diagram shows a functional relationship
Gre4nikov [31]

Answer:

f(4)=\frac{1}{2}

f(x) = 4 when x is 8

Step-by-step explanation:

Domain is the set of x values that make the function defined. Allowed x values for the function (mapping).

The Range is the set of y values that make the function defined. Allowed y values for the function (mapping).

  • Whenever we need to find f(a), suppose, then we look for "a" in the domain and see its corresponding value mapping in the range.
  • Whenever we will be given a value for f(x) = a, suppose, and we have to find "x", we look at the value a in the range and find corresponding x value in the domain.

Firstly, we need f(4), so we look for "4" in domain and see which number it corresponds to in range.

That is \frac{1}{2}

Thus,

f(4)=\frac{1}{2}

Next,

We want "x" value that gives us a "y" value of 4. We look for "4" in the range and see which value it corresponds to. That is "8". So,

f(8) = 4

8 0
3 years ago
5x + 2y = 3<br> 2x+3y=-1<br> Solve
professor190 [17]

Answer:

x = 1

y = -1

Point = (1,-1)

Step-by-step explanation:

2x + 3y = -1   =   y = -2/3 - 1/3

5x + 2(-2/3 - 1/3) = 3

5x - 1 1/3 - 2/3 = 3

5x - 2 = 3

<u>     +2    +2</u>

5x = 5

<em><u>x = 1</u></em>

2(1) + 3y = -1

2 + 3y = -1

<u>-2           -2</u>

3y = -3

<em><u>y = -1</u></em>

3 0
2 years ago
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