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VARVARA [1.3K]
2 years ago
12

GRADE 11 MATH

Mathematics
1 answer:
Romashka-Z-Leto [24]2 years ago
4 0

The amount that was invested 17 years ago is $2064.25.

The interest earned is  $7935.75.

<h3>What is the amount invested 17 years ago?</h3>

The formula that would used to determine the amount that was invested 17 years ago is:

P = FV / (1 + r)^nm

Where:

  • FV = Future value = 10,000
  • P = Present value
  • R = interest rate = 9.5 / 2 = 4.75%
  • m = number of compounding = 2
  • N = number of years = 17

10,000 / (1.0475)^(17 x 2) = $2064.25

Interest earned = 10,000 - 2064.25 = $7935.75

To learn more about future value, please check: brainly.com/question/18760477

#SPJ1

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An automobile insurance company issues a one-year policy with a deductible of 500. The probability is 0.8 that the insured autom
Effectus [21]

Answer:

y₀.₉₅ = 3659

Step-by-step explanation:

P( no accident ) = 0.8

P( one accident ) = 0

deductible = 500

mean = 3000

<u>Determine the 95th percentile of the insurance company payout </u>

Assuming : y =company payout , x =amount of loss incurred due to accident

Then :

P( x < 500 ) = 0.2 ( 1 - e^-500/3000)

                   = 0.2 ( 1 - e^-1/6 )

95th percentile =

= P( y < y₀.₉₅  ) 0.95

  P( y = 0 ) = 0.8 + 0.2 ( 1 - e^-1/6 ) = 0.8307

attached below is the remainder of the solution

5 0
3 years ago
What’s the conjugate of 2x+3
quester [9]

Answer:

2x-3

Step-by-step explanation:

4 0
3 years ago
If it takes 6 hours for a plane to travel 720km with a tail wind and 8 hours to make the return trip with a head wind. Find the
denis-greek [22]

The speed of wind and plane are 105 kmph and 15 kmph respectively.

<u>Solution:</u>

Given, it takes 6 hours for a plane to travel 720 km with a tail wind and 8 hours to make the return trip with a head wind.  

We have to find the air speed of the plane and speed of the wind.

Now, let the speed wind be "a" and speed of aeroplane be "b"

And, we know that, distance = speed x time.

\text { Now, at tail wind } \rightarrow 720=(a+b) \times 6 \rightarrow a+b=\frac{720}{6} \rightarrow a+b=120 \rightarrow(1)

Now at head wind → 720=(a-b) \times 8 \rightarrow a-b=\frac{720}{8} \rightarrow a-b=90 \rightarrow(2)

So, solve (1) and (2) by addition

2a = 210

a = 105

substitute a value in (1) ⇒ 105 + b = 120

⇒ b = 120 – 105 ⇒ b = 15.

Here, relative speed of plane during tail wind is 120 kmph and during head wind is 90 kmph.

Hence, speed of wind and plane are 105 kmph and 15 kmph respectively.

6 0
3 years ago
What is the equation of the line that passes through the points (1,5) and (0,3)?
Pavlova-9 [17]

Answer:

y=2x+3

Step-by-step explanation:

first use the y2-y1/x2-x1 then use y=mx+b after

plug in 3 for y2 and 5 for y1

then plug in 0 for x2 and 1 for x1

\frac{3-5}{0-1}=\frac{-2}{-1} =2 and 2 is ur slope

___________________

now use y=mx+b

i usually use the first point but u can u anyone u want

plug in 1 for x

plug in 5 for y

and plug in 2 for m

5=2(1)+b

5=2+b

subtract 2 on both sides

5-2=3

3=b and b is ur y-intercept

y=2x+3

hope this helps

4 0
3 years ago
Find the midpoint of R(2,2) and S(-3,6)
musickatia [10]

Answer: (-0.5, 4)

Step-by-step explanation:

Midpoint formula: (\frac{x1+x2}{2} ,\frac{y1+y2}{2} )

(x1, x2)=(2, -3)

(y1, y2)=(2, 6)

-----------------------------------------------

 (\frac{x1+x2}{2} ,\frac{y1+y2}{2} )

=(\frac{2-3}{2} ,\frac{2+6}{2} )

=(\frac{-1}{2} ,\frac{8}{2} )

=(-0.5, 4)

Hope this helps!! :)

Please let me know if you have any question or need further explanation

3 0
3 years ago
Read 2 more answers
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