For this case, the first thing we must do is calculate the total cost.
We have then:
C = (16) * (2.4) * (6)
C = 230.4 $
Then, the change it receives is given by:
250 - 230.4 = 19.6 $
Answer:
He has received 19.6 $ from $ 250
So if we see the first one (8,4) x=8 and y=4
And we see the 2nd one (4,y) x=4 and y=?
We notice that the value of x its been halved. So y varies with x so y value also has to be halved so y= 2
Step-by-step explanation:
as in the other problem, the table describes mutually exclusive attributes.
so, we can simply sum the numbers up to get the total number of students :
3+9+2+16 = 30 students.
so, when picking a random student, we have 30 possibilities.
now, how many of those 30 have the desired attributes (to have a brother AND a sister) ?
I see 3 in the table.
so, the probability to pick a student that has a brother and a sister is
3/30 = 1/10 = 0.1
Sector area can be found with the formula
where
is the central angle.
r = 8m ,
= 135º
m^2
Arc length formula is 
m