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son4ous [18]
2 years ago
12

Please help me with this question I’m so confused

Mathematics
2 answers:
Arisa [49]2 years ago
6 0

Answer:

4.75

Step-by-step explanation:

i hope this is helpful to you.

zavuch27 [327]2 years ago
4 0

s = ut +  \frac{1}{2} a {t}^{2}  \\ s = 10( \frac{1}{2} ) +  \frac{1}{2} ( - 2) {( \frac{1}{2}) }^{2}  \\ s = 10( \frac{1}{2} ) +  \frac{1}{2} ( - 2)(  \frac{1}{4} ) \\ s = 5 + ( - 1)( \frac{1}{4} ) \\ s = 5 + ( -  \frac{1}{4} ) \\ s = 5 -  \frac{1}{4}  \\ s =  \frac{20}{4}  -  \frac{1}{4}  \\ s =  \frac{19}{4}

Hope it helps

Please give brainliest

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the first solution is 20% acid, and say we'll be using "x" liters, so how many liters of just acid are in it?  well 20% of "x" or namely 0.2x.  Likewise for the 60% acid solution, if we had "y" liters of it, the amount of only acid in it is 0.6y.

\begin{array}{lcccl} &\stackrel{solution}{quantity}&\stackrel{\textit{\% of }}{amount}&\stackrel{\textit{liters of }}{amount}\\ \cline{2-4}&\\ \textit{1st solution}&x&0.20&0.2x\\ \textit{2nd solution}&y&0.60&0.6y\\ \cline{2-4}&\\ mixture&100&0.44&44 \end{array}~\hfill \begin{cases} x+y=100\\\\ 0.2x+0.6y=44 \end{cases}

x+y=100\implies y=100-x~\hfill \stackrel{\textit{substituting on the 2nd equation}}{0.2x+0.6(100-x)=44} \\\\\\ 0.2x+60-0.6x=44\implies -0.4x+60=44\implies -0.4x=-16 \\\\\\ x=\cfrac{-16}{-0.4}\implies \boxed{x=40}~\hfill \boxed{\stackrel{100-40}{y=60}}

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2 years ago
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Hello, 

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3 years ago
Read 2 more answers
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