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Naya [18.7K]
3 years ago
9

Pens cost $p exercise books cost $b. Write an algebraic expression that represent the cost of purchasing 20 pens and 8 exercise

books.
Mathematics
2 answers:
strojnjashka [21]3 years ago
6 0

Answer:

20p+8b

Step-by-step explanation:

pens=p

books=b there fore

20p+8b

Blababa [14]3 years ago
4 0

Answer:

Step-by-step explanation:

Cost of one pen = $p

Cost of 20 pens = p*20 = 20p

Cost of  an exercise book = $b

Cost of 8 exercise book = b*8 = 8b

Algebraic expression:

20p + 8b

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The area of a rectangle is 63 m2 , and the length of the rectangle is 5 m more than double the width. find the dimensions of the
Kamila [148]
If you let x represent the width of the rectangle, then you can write the equation for area as
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7 0
3 years ago
Victoria has 2.50 pounds of bell peppers and the cost is $1.25. What is the price for 1 pound of bell peppers?
AleksAgata [21]

Answer:

The price of one pound of bell peppers is $0.6.

Step-by-step explanation:

This problem is equivalent to the following:

<em>"if 10 oranges cost $20, how much does 1 orange cost? "</em>

and the answer to that question is:

price of 1 orange  = $20/ 10 oranges = $2 per orange.

Put simply, we divided the total price by the total number of items, and we shall do the same thing for the case of bell peppers:

price of 1 pound  = $1.25/ 2.5 pounds = $0.5/ pound.

The price for 1 pound of bell peppers is $0.5.

8 0
4 years ago
40Points? CORRECT answer please
irina [24]

Answer:

<h2>f(-2) = 12.5</h2>

Step-by-step explanation:

f(t)=2(0.4)^t

f(-2) → put t = -2 to the equation of the function:

f(-2)=2(0.4)^{-2}=2\left(\dfrac{4}{10}\right)^{-2}=2\left(\dfrac{2}{5}\right)^{-2}

Use a^{-n}=\left(\dfrac{1}{a}\right)^n

f(-2)=2\left(\dfrac{5}{2}\right)^2=2\left(\dfrac{25}{4}\right)=\dfrac{25}{2}=12.5

3 0
3 years ago
Two similar cylinders have radii of 15 inches and 6 inches. What is the ratio of the surface area of the small cylinder to the s
Levart [38]

Answer:

4:25

Step-by-step explanation:

Given that,

r₁ = 15 inches, r₂ = 6 inches

The area of the cylinder is given by :

A=2\pi rh+2\pi r^2

The ratio of surface areas of two cylinders,

\dfrac{S_2}{S_1}=\dfrac{2\pi r_2h_2+2\pi r_2^2}{2\pi r_1h_1+2\pi r_1^2}\\\\\dfrac{S_2}{S_1}=(\dfrac{r_2}{r_1})^2\\\\=\dfrac{6}{15}^2\\\\=\dfrac{4}{25}

Hence, the required ratio is 4:25.

8 0
3 years ago
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