All categories

2 years ago

PLEASE HELP!!!

Mathematics

1 answer:

kramer2 years ago

6 0

The arc is defined by an angle of 1.05 radians, and a length of 1.05 units.

<h3 /><h3>How to get the angle in radians?</h3>

Remember the relation:

180° = 3.14 radians.

Then:

60° = (60°/180°)*3.14 rad = 1.05 rad.

Now, for a circle of radius R, an arc defined by an angle θ has a length:

L = θ*R

Then the length of this arc is:

L = 1.05*1 unit = 1.05 units.

If you want to learn more about arcs:

brainly.com/question/2005046

#SPJ1

You might be interested in

F(n+1)=f(n)-8 if f(1)=100 what is f(6)

Svet_ta [14]

$f(n+1)=f(n)-8\\\\ f(2)=100-8=92\\ f(3)=92-8=84\\ f(4)=84-8=76\\ f(5)=76-8=68\\ f(6)=68-8=60$

8 0

3 years ago

Round the factors to estimate the product 697 x 82

KonstantinChe [14]

Estimated would be 700 x 80

3 0

3 years ago

Read 2 more answers

Help meeeeeeeeeeeeeeee

laila [671]

Answer:

Step-by-step explanation:

Complementary angles are two angles whose measures add to 90°.

m<CFD = 150° - 100° = 50°

m<EFD = 180° - 150° = 30°

Sum = 80°

m<AFB = 40°

m<DFE = m<EFD = 30°

Sum = 70°

m<AFC = 100°

Sum > 100°

m<BFC = 100° - 40° = 60°

m<DFE = 30°

Sum = 90°

Yes

Answer: D.

8 0

2 years ago

A juggler tosses a ball into the air . The balls height, h and time t seconds can be represented by the equation h(t)= -16t^2+40

malfutka [58]

PART A

The given equation is

$h(t) = - 16 {t}^{2} + 40t + 4$

In order to find the maximum height, we write the function in the vertex form.

We factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + 4$

We add and subtract

$- 16(- \frac{5}{4} )^{2}$

to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t) + - 16( - \frac{5}{4})^{2} - -16( - \frac{5}{4})^{2} + 4$

We again factor -16 out of the first two terms to get,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4})^{2} ) - -16( - \frac{5}{4})^{2} + 4$

This implies that,

$h(t) = - 16 ({t}^{2} - \frac{5}{2} t + ( - \frac{5}{4}) ^{2} ) + 16( \frac{25}{16}) + 4$

The quadratic trinomial above is a perfect square.

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +25+ 4$

This finally simplifies to,

$h(t) = - 16 ( t- \frac{5}{4}) ^{2} +29$

The vertex of this function is

$V( \frac{5}{4} ,29)$

The y-value of the vertex is the maximum value.

Therefore the maximum value is,

$29$

PART B

When the ball hits the ground,

$h(t) = 0$

This implies that,

$- 16 ( t- \frac{5}{4}) ^{2} +29 = 0$

We add -29 to both sides to get,

$- 16 ( t- \frac{5}{4}) ^{2} = - 29$

This implies that,

$( t- \frac{5}{4}) ^{2} = \frac{29}{16}$

$t- \frac{5}{4} = \pm \sqrt{ \frac{29}{16} }$

$t = \frac{5}{4} \pm \frac{ \sqrt{29} }{4}$

$t = \frac{ 5 + \sqrt{29} }{4} = 2.60$

or

$t = \frac{ 5 - \sqrt{29} }{4} = - 0.10$

Since time cannot be negative, we discard the negative value and pick,

$t = 2.60s$

8 0

3 years ago

A car dealership is trying to sell all of the cars that are on the lot. If there are 675 cars on the lot and they sell 45 cars p

Lisa [10]

Around 14 weeks

45*14=630
675-630=45

So around 14 weeks

8 0

3 years ago