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Shkiper50 [21]
2 years ago
13

Match each equation to the line of best fit that it models.

Mathematics
1 answer:
egoroff_w [7]2 years ago
6 0

By applying concepts of <em>linear</em> functions, the graphs are related to the following expressions:

  1. (4/7) · x + 2
  2. x + 2
  3. (1/7) · x + 2
  4. - (1/7) · x + 2
  5. - x + 2

<h3>How to match a line with a given linear function</h3>

Graphically speaking, lines are described by <em>linear</em> functions, a kind of polynomials of grade 1, whose standard form is presented below:

y = m · x + b     (1)

Where:

  • x - Independent variable
  • y - Dependent variable
  • m - Slope
  • b - Intercept

Please notice that the slope is represented graphically by the change in the y-variable divided by the change in the x-variable and the intercept is the location where the line passes through the y-axis. Hence, the <em>resulting</em> expressions are shown in this order:

  1. (4/7) · x + 2
  2. x + 2
  3. (1/7) · x + 2
  4. - (1/7) · x + 2
  5. - x + 2

To learn more on linear functions: brainly.com/question/9330192

#SPJ1

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The school store opened on the first day of school with 45 notebooks and 15 pencils. Within two days it sold all of these items.
malfutka [58]

The number of pencils sold on the first day  is 5 pencils.

The number of notebooks sold on the first day  is 10 notebooks.

The number of pencils sold on the second day 10 pencils.

The number of notebooks sold on the second day   35 notebooks.

<u>Step-by-step explanation:</u>

Given data,

  • The total number of notebooks in the store = 45 notebooks.
  • The total number of Pencils in the store = 15 pencils.
  • The number of days that all items were sold = 2 days.

Now, you have to calculate the no.of notebooks and no. of pencils sold each day.

<u>In the first day :</u>

The number of sale of notebooks and pencils are given by,

Twice as many notebooks were sold as pencils.

Let us take, the number of pencils sold on the first day  = x

And,  the number of notebooks sold on the first day  = 2x (Twice as pencils).

<u>In the second day :</u>

The number of sale of notebooks and pencils are given by,

For every 7 notebooks​ sold, 2 pencils were sold.

The number of pencils sold on the second day =   2y

The number of notebooks sold on the second day   = 7y

<u> The equation is framed for number of notebooks sold on each day :</u>

The number of notebooks sold ⇒ 2x + 7y = 45   -------(1)

<u> The equation  is framed for number of pencils sold on each day :</u>

The number of pencils sold: x + 2y = 15  ----------(2)

Solving the equations by multiplying eq(2) by 2 and subtract it from eq(1),

  2x + 7y = 45

-<u> (2x + 4y) = 30</u>

   <u>        3y = 15  </u>

⇒ y = 15/3

⇒ y = 5

The value of y is 5.

Substitute y=5 in eq (2),

⇒ x + 2(5) = 15

⇒ x + 10 = 15

⇒ x = 15 - 10

⇒ x = 5

The value of x is 5.

First day sale,

The number of pencils sold on the first day  = x ⇒ 5 pencils

The number of notebooks sold on the first day  = 2x ⇒ 10 notebooks

Second day sale,

The number of pencils sold on the second day =   2y ⇒ 10 pencils

The number of notebooks sold on the second day   = 7y ⇒ 35 notebooks.

8 0
3 years ago
Please help me with this sum I will mark you as brainest​
Murljashka [212]

Answer:

Step-by-step explanation:

3/6 x 8

= ( 3 x 8 ) / 6

= 24 / 6

4/7 x 2

= ( 4 x 2 ) / 7

= 8 / 7

9/2 x 3

= ( 9 x 3 ) / 2

= 27 / 2

8/5 x 7

= ( 8 x 7 ) / 5

= 56 / 5

3/9 x 5

= ( 3 x 5 ) / 9

= 15/9

7/4 x 4

= ( 7 x 4 ) / 4

= 28 / 4

6/2 x 6

= ( 6 x 6 ) / 2

= 36 / 2

8/3 x 9

= ( 8 x 9 ) / 3

= 72 / 3

9/4 x 8

= ( 9 x 8 ) / 4

= 72 / 4

5/3 x 6

= ( 5 x 6 ) / 3

= 30 / 3

2/7 x 3

= ( 2 x 3 ) / 7

= 6 / 7

8/4 x 7

= ( 8 x 7 ) / 4

= 72 / 4

6/4 x 2

= ( 6 x 2 ) / 4

= 12 / 4

3 0
3 years ago
4xy + 10yᒾ<br> Tui mún hỏii
slavikrds [6]

Answer:

4xy+10y²=2y(2x+5y)

Hope it helps!!!

3 0
3 years ago
42.6 is 66 2/3% of what number?
Elza [17]

42.6 is 66 2/3% of 63.9

the answer is : 63.9

4 0
3 years ago
PLEASE HELP!!!! THIS IS TIMED!!!!! PLEASE HELP ME!!!!! PLEASE!!!!!!!!!!!!!!!
kodGreya [7K]
1 is the answer!
good luck
5 0
3 years ago
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