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UNO [17]
3 years ago
6

The velocity v of the flow of blood at a distance r from the central axis of an artery of radius R is given below, where k is th

e constant proportionality. v = k(R2 − r2) Find the average rate of flow of blood along a radius of the artery. (Use 0 and R as the limits of integration.)
Mathematics
1 answer:
andrew11 [14]3 years ago
3 0
The average rate of blood flow is given by

\displaystyle\frac1{R-0}\int_0^Rv(r)\,\mathrm dr=\frac kR\int_0^R(R^2-r^2)\,\mathrm dr
=\dfrac kR\left(R^2r-\dfrac13r^3\right)\bigg|_{r=0}^{r=R}
=\dfrac kR\left(R^3-\dfrac13R^3\right)
=\dfrac{2kR^2}3
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when the degree of P(x)=q(x), then divide the leading coefient of P(x) by the leading coeficnet of q(x)
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ok so for vertical assymtote example
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This is the correct answer. Not satisfied? Check out this answer expert verified answer of the same question but with a step-by-step explanation. This answer is just a simple version of rocioo's correct answer.

Expert Verified Answer (of this same question but with a step-by-step explanation):

This is the link to rocioo's answer. <u>brainly.com/question/13675950</u>

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