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UNO [17]
3 years ago
6

The velocity v of the flow of blood at a distance r from the central axis of an artery of radius R is given below, where k is th

e constant proportionality. v = k(R2 − r2) Find the average rate of flow of blood along a radius of the artery. (Use 0 and R as the limits of integration.)
Mathematics
1 answer:
andrew11 [14]3 years ago
3 0
The average rate of blood flow is given by

\displaystyle\frac1{R-0}\int_0^Rv(r)\,\mathrm dr=\frac kR\int_0^R(R^2-r^2)\,\mathrm dr
=\dfrac kR\left(R^2r-\dfrac13r^3\right)\bigg|_{r=0}^{r=R}
=\dfrac kR\left(R^3-\dfrac13R^3\right)
=\dfrac{2kR^2}3
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To solve this, we are going to use the slope formula, and the point slope formula.
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where
m is the slope.
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(x_{2},y_{2})  are the coordinates of the first point.
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Plan A. Coordinates of the first point: (1,14) (number of discs, cost). Coordinates of the second point: (2,17). Lets replace those values in our slope formula:
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Plan B. Coordinates of the first point (1,12). Coordinates of the second point (2,16).
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y-y_{1}=m(x-x_{1})
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Part D. Coordinates of the first point: (1,12). Coordinates of the second point (2,21).
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Answer:

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