There are 30 biscuits in a tin. 8 of the biscuits are iced, of which 6 contain

Mathematics

1 answer:

amid [387]2 years ago

5 0

The probability that a biscuit picked at random contains chocolate

chips. = 1/5 , The Venn Diagram is attached with the answer.

<h3>What is Probability ?</h3>

Probability is defined as the study of likeliness of an event to happen.

It is given that

There are 30 biscuits in a tin

8 of the biscuits are iced, of which 6 contain chocolate chips

4 biscuits are neither iced nor contain chocolate chips.

the probability that a biscuit picked at random contains chocolate

chips.

There are total 6 biscuits which have chocolate chips

The probability that a biscuit picked at random contains chocolate

chips. = 6/8 *8/30 = 6/30 = 1/5

The probability that a biscuit picked at random contains chocolate

chips. = 1/5

The Venn Diagram is attached with the answer.

To know more about Probability

brainly.com/question/11234923

#SPJ1

You might be interested in

An animal sanctuary currently has 125 elk in it. The elk are expected to increase by 20% each year. How many elk will there be i

seropon [69]

There will be 200 elk after 3 years

6 0

3 years ago

What expressions are equivalent to 4x-5

Vitek1552 [10]

Answer:

2(2x-2.5)

4(x-1.25)

5(0.8x-1)

Step-by-step explanation:

8 0

2 years ago

Read 2 more answers

Write an equation in standard form of the hyperbola described.

marishachu [46]

Check the picture below, so the hyperbola looks more or less like so, so let's find the length of the conjugate axis, or namely let's find the "b" component.

$\textit{hyperbolas, horizontal traverse axis } \\\\ \cfrac{(x- h)^2}{ a^2}-\cfrac{(y- k)^2}{ b^2}=1 \qquad \begin{cases} center\ ( h, k)\\ vertices\ ( h\pm a, k)\\ c=\textit{distance from}\\ \qquad \textit{center to foci}\\ \qquad \sqrt{ a ^2 + b ^2} \end{cases} \\\\[-0.35em] ~\dotfill$

$\begin{cases} h=0\\ k=0\\ a=2\\ c=4 \end{cases}\implies \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{b^2} \\\\\\ c^2=a^2+b^2\implies 4^2=2^2+b^2\implies 16=4+b^2\implies \underline{12=b^2} \\\\\\ \cfrac{(x-0)^2}{2^2}-\cfrac{(y-0)^2}{12}\implies \boxed{\cfrac{x^2}{4}-\cfrac{y^2}{12}}$