1.-7/4
2.1/7
3.-5/3
4.1/2
5.neither a parallelogram nor a trapezoid
6.neither pair of opposite sides is parallel
hope this help any one who need the answer <span />
This is an incomplete question, here is a complete question and image is also attached below.
How much longer is the hypotenuse of the triangle than its shorter leg?
a. 2 ft
b. 4 ft
c. 8 ft
d. 10 ft
Answer : The correct option is, (b) 4 ft
Step-by-step explanation:
Using Pythagoras theorem in ΔACB :
Given:
Side AC = 6 ft
Side BC = 8 ft
Now put all the values in the above expression, we get the value of side AB.
Now we have to calculate the how much longer is the hypotenuse of the triangle than its shorter leg.
Difference = Side AB - Side AC
Difference = 10 ft - 6 ft
Difference = 4 ft
Therefore, the 4 ft longer is the hypotenuse of the triangle than its shorter leg.
Answer:
1 hour
Step-by-step explanation:
Hello, let's say that her departure trip takes t in minutes, as her return speed is 3 times her departure speed, she took t/3 for the return and we know that this 40 minutes less, so we can write.
t/3=t-40
We can multiply by 3
t = 3t -40*3 = 3t - 120
This is equivalent to
3t -120 = t
We subtract t
2t-120 = 0
2t = 120
We divide by 2
t = 120/2 = 60
So this is 60 minutes = 1 hour.
Thank you.
Answer:
0
Step-by-step explanation:
Well average means mean so we have to find the mean of the numbers in the data set. Our numbers are -12,12,-4, and finally 4. When we add all of them up we get 0 and we have to divide 0 by the 4 thermoters and your answer is 0. if this is confusing just leave a comment and ill try to explain better
First, lets transform the given vector into an unit vector (dividing by its module)
UnitVec = 4/5 i + 3/5 j
Then lets change this vector into a polar form
UnitVec = 1. with angle of 36.869 degrees taking as a reference the i vector
Then, the probem tells us that the vectors u and v make an angle of 45 degrees with UnitVec, so lets add+-45 to the vector in polar form
U = 1*[cos(36.869 +45)i + sin(36.869 +45)j] = 0.1414 i + 0.9899 j
V = 1*[cos(36.869 -45)i + sin(36.869 -45)j] = 0.9899 i - 0.1414 j
