<span>The organic molecules that must be included in the soil for earthworm nutrition are Neutral pH. A neutral pH substance that is neither basic nor acidic is considered neutral. The pH scale is the one that measures how a substance is basic or acidic. It ranges from 0-14. A 7 pH is neutral.</span>
The extra oxygen is used to restore muscle fibers to their pre-exercise state by doing all of the following except facilitating calcium release from the sarcoplasmic reticulum in the muscle fiber. Thus, the correct option is B.
<h3>What is Respiration?</h3>
Respiration may be defined as the process of acquiring oxygen from outside the body and utilizing it in the process of breakdown of food sources for cellular needs.
The extra oxygen works in the muscle fiber by replenishing the ATP, restocking the myoglobin, and supplying the ATP used to replenish glycogen stores in the muscle fiber.
Therefore, the correct option for this question is B.
To learn more about Respiration, refer to the link;
brainly.com/question/18169685
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Answer: 8hrs
Explanation:
G1 phase is the intermediate phase between the end if cell division and the beginning of DNA replication.
Thus to get the duration of the G1 phase = 1/3 × 24hrs = 8hrs
It is the last one if more eggs are produced by chickens they will lose more weight
Answer:
frequency of the blue (B) allele 
frequency of the red (R) allele 
The number of blue plants expected is 
The number of red plants expected is 
The anticipated number of violet plants is 
Calculated chi square value
Explanation:
Frequency of blue allele is
Frequency of blue allele is equal to sum of frequency of BB and half of frequency of BR

Frequency of other allele

Chi Square test
See the attached file
The number of blue plants expected is 
The number of red plants expected is 
The anticipated number of violet plants is 
Calculated chi square value