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2 years ago

9

Joe and Steve are saving money. Joe starts with $105 and save $5 a week. Steve starts with $5 and saves $15 per week. After how

many weeks will they have the same amount of money?

1 answer:

Margaret [11]2 years ago

6 0

Answer:

10

Step-by-step explanation:

y= 5x+105,y=15x+5 are the equations. Use them and you should get 10 weeks ($155)

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What must be true of PQ?

yulyashka [42]

Interesting question
Usually when you look at something like that construction, you think that AB has been bisected by PQ and that the two segments are perpendicular. They are perpendicular but nowhere is that stated. So the answer is C because all the other answers are wrong.

PQ is congruent AB is not correct. As long as the arcs are equal and meet above and below AB there is no proof of congruency. In your mind widen the compass legs so that they are wider than AB and redraw the arcs. You get a larger PQ, but it has all the original properties of PQ except size.

PQ is not congruent to AQ. How would you prove conguency? You'd have to put both lines into triangles that can be proved congruent. It can't be done.

The two lines are not parallel. They are perpendicular. That can be proven. They meet at right angles to each other (also provable).

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3 years ago

Solve the equation 3/4x+3-2x = -1/4+1/2x+5

elena55 [62]

Hi there! The answer is x = -1

Let's solve this equation step by step!
$\frac{3}{4} x + 3 - 2x = - \frac{1}{4} + \frac{1}{2} x + 5$

First collect terms.
$- 1 \frac{1}{4} x + 3 = \frac{1}{2} x + 4 \frac{3}{4}$

Subtract (1/2)x from both sides.
$- 1\frac{3}{4} x + 3 = 4 \frac{3}{4}$

Subtract 3 from both sides.
$- 1\frac{3}{4} x = 1 \frac{3}{4}$

And finally divide by -1 3/4
$x = \frac{7}{4} \div - \frac{7}{4} = \frac{7}{4} \times - \frac{4}{7} = - \frac{28}{28} = - 1$

8 0

3 years ago

Read 2 more answers

66 athletes are running a race. A gold medal is to be given to the winner, a silver medal is to be

Dmitrij [34]

Answer:

274560

Step-by-step explanation:

We can "choose" one of the 66 athletes for the gold medal. That athlete can't win any other medals, so there are 65 athletes left.

We can then "choose" one of the 65 athletes left for the silver medal. That athlete can't win any other medals, so there are 64 athletes left.

We can then "choose" one of the 64 athletes left for the bronze medal.

That leaves us with 66 possible choices * 65 possible choices * 64 possible choices=274560 possible choices

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2 years ago

From a random sample of 58 businesses, it is found that the mean time the owner spends on administrative issues each week is 21.

zzz [600]

Answer: (20.86, 22.52)

Step-by-step explanation:

Formula to find the confidence interval for population mean :-

$\overline{x}\pm z^*\dfrac{\sigma}{\sqrt{n}}$

, where $\overline{x}$ = sample mean.

z*= critical z-value

n= sample size.

$\sigma$ = Population standard deviation.

By considering the given question , we have

$\overline{x}= 21.69$

$\sigma=3.23$

n= 58

Using z-table, the critical z-value for 95% confidence = z* = 1.96

Then, 95% confidence interval for the amount of time spent on administrative issues will be :

$21.69\pm (1.96)\dfrac{3.23}{\sqrt{58}}$

$=21.69\pm (1.96)\dfrac{1.7}{7.61577}$

$=21.69\pm (1.96)(0.223221)$

$\approx21.69\pm0.83$

$=(21.69-0.83,\ 21.69+0.83)=(20.86,\ 22.52)$

Hence, the 95% confidence interval for the amount of time spent on administrative issues = (20.86, 22.52)

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3 years ago

Given that x overbarequals3.6667, s Subscript xequals2.0656, y overbarequals4.2167, s Subscript yequals1.5613, and requalsne

Shtirlitz [24]

Answer:

$y = 0.7063x+2.7790$

Step-by-step explanation:

Given that

$x bar = 3.6667\\s_x= 2.0656\\y bar = 4.2167\\s_7 = 1.5613\\r = -0.9344$

We have slope of linear regression line is

$a=r*\frac{s_y}{s_x} =0.9344(\frac{1.5613}{2.0656} )\\=0.7063$

So regression line would be of the form

$y-4.2167 = 0.7063(x-2.0656)$ (since it passes through xbar, y bar)

$y = 0.7063x+2.7790$

is the equation of regression line.

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3 years ago