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il63 [147K]
2 years ago
6

Find the missing side of this right

Mathematics
1 answer:
lidiya [134]2 years ago
7 0

Answer:

8

Step-by-step explanation:

If we assume the '17' is the hypotenuse ( the Q does not say)

then    15^2  + x^2 = 17^2   via the pythag theorem for right triangles

           x = 8

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Heidi earns $11.50 per hour plus a bonus of $105 for the week. Her goal is to earn $650 for the week. Which equation
Stells [14]

Answer:

48 hours

Step-by-step explanation:

$650 - $105 = $545

$545 ÷ $11.50 = 47.39 = 48 hours (Rounded)

6 0
2 years ago
I need to know what the ansswer is to this we are doing pemdas
mamaluj [8]

Answer:

18

Step-by-step explanation:

10-4+6(4-2)

10-4+6(2)

10-4+12

6+12

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3 years ago
A grocery store sells a bag of 5 avocados for $4. What is the unit cost of each avocado?
weeeeeb [17]
5x4 = 20
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2 years ago
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The exact volume is what?
Galina-37 [17]

Answer:

7680πyd³

Step-by-step explanation:

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= πr²h

= 16² * 30 * π

= 7680 π yd³

Hope it will help :)❤

7 0
3 years ago
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For how many real values of x is <img src="https://tex.z-dn.net/?f=%20%5Csqrt%7B120-%5Csqrt%7Bx%7D%7D%20" id="TexFormula1" title
leva [86]

A good place to start is to set \sqrt{x} to y. That would mean we are looking for \sqrt{120-y} to be an integer. Clearly, y\leq 120, because if y were greater the part under the radical would be a negative, making the radical an imaginary number, not an integer. Also note that since \sqrt{x} is a radical, it only outputs values from [0,\infty], which means y is on the closed interval: [0,120].

With that, we don't really have to consider y anymore, since we know the interval that \sqrt{x} is on.

Now, we don't even have to find the x values. Note that only 11 perfect squares lie on the interval [0,120], which means there are at most 11 numbers that x can be which make the radical an integer. All of the perfect squares are easily constructed. We can say that if k is an arbitrary integer between 0 and 11 then:

\sqrt{120-\sqrt{x}}=k \implies \\ \sqrt{x}=k^2-120 \implies\\ x=(k^2-120)^2

Which is strictly positive so we know for sure that all 11 numbers on the closed interval will yield a valid x that makes the radical an integer.

5 0
3 years ago
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