Ask question

Ask question

All categories

3 years ago

7

Some students want to know if residents of their town are in favor of building a new school. Kevin surveys all of the residents

in his neighborhood.Identify Kevin’s type of sampling method.
systematic
convenience
self-select
random

1 answer:

Olegator [25]3 years ago

4 0

i think systematic

could you answer my latest question

You might be interested in

Answer to this problem <br> 2³×(15-9)+7

Crazy boy [7]

Answer:

The answer is 55.

Step-by-step explanation:

hope this helps

2³×(15-9)+7

=8(15-9)+7

=120-72+7

=48+7

=55

6 0

3 years ago

Read 2 more answers

Please help me on this

garri49 [273]

Answer:

It's not specific enough, I'll come back to you!

6 0

3 years ago

The sides of an isosceles triangle are 8, 8, and 3. The measure of the vertex angle to the nearest degree is _____°. 44 17 31 22

Doss [256]

We may draw a vertical that bisects the vertex angle and the shorter side of the triangle, to form a right-triangle with the measurements:
hypotenuse = 8
length = 1.5

We may then apply:
sin(∅) = P / H
sin(∅) = 1.5 / 8
∅ = 10.8 ≈ 11°

This is half of the vertex angle, so the vertex angle is:
11 * 2 = 22°

4 0

3 years ago

Read 2 more answers

Bill is building a deck. He wants the length of the deck to be 7 feet. If he wants the area of the deck to be 105 square feet, w

kotykmax [81]

The answer is 15 feet

5 0

2 years ago

Daily high temperatures in St. Louis for the last week were as follows: 95, 92, 93, 92, 95, 90, 90 (yesterday). a) The

hichkok12 [17]

Answer:

a) T = 91.7 degrees

b) T = 90 degrees

c) MAD = 1.9

d) MSE = 5.05

Step-by-step explanation:

Given:

- Daily high temperatures in St. Louis for the last week were as follows:

95, 92, 93, 92, 95, 90, 90

Find:

a) Forecast the high temperature today, using a 3-day moving average.

b) Forecast the high temperature today, using a 2-day moving average.

c) Calculate the mean absolute deviation based on a 2-day moving average, covering all days in which you can have a forecast and an actual temperature.

d) The mean squared error for the 2-day moving average

Solution:

a)

- The set of 3 day moving average is as follows:

4. (95 + 92 + 93) ÷ 3 = 93.33⁰C

5. (92 + 93 + 92) ÷ 3 = 92.33⁰C

6. (93 + 92 + 95) ÷ 3 = 93.33⁰C

7. (92 + 95 + 90) ÷ 3 = 92.33⁰C

8. (95 + 90 + 90) ÷ 3 = 91.667⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 91.7 degrees

b)

- The set of 2 day moving average is as follows:

3. (95 + 92) ÷ 2 = 93.5⁰C

4. (95 + 93) ÷ 2 = 92.5⁰C

5. (93 + 92) ÷ 2 = 92.5⁰C

6. (92 + 95) ÷ 2 = 93.5⁰C

7. (95 + 90) ÷ 2 = 92.5⁰C

8. (90 + 90) ÷ 2 = 90⁰C

- Now use these points on excel sheet to forecast the temperature for today. The line of best fit is given:

T = 90 degrees

c)

Error Error^2

3. 93.5⁰C 0.5 0.25

4. 92.5⁰C 0.5 0.25

5. 92.5⁰C 2.5 6.25

6. 93.5⁰C 3.5 12.25

7. 92.5⁰C 2.5 6.25

8. 90⁰C

- The mean absolute deviation as follows:

MAD = Sum of all errors / 5

MAD = (0.5+0.5+2.5+3.5+2.5) / 5

MAD = 1.9

d)

- The mean squared error deviation as follows:

MSE = Sum of all error^2 / 5

MSE = (0.25+0.25+6.25+12.25+6.25) / 5

MSE = 5.05

4 0

3 years ago