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RideAnS [48]
3 years ago
7

Some students want to know if residents of their town are in favor of building a new school. Kevin surveys all of the residents

in his neighborhood.Identify Kevin’s type of sampling method.
systematic
convenience
self-select
random
Mathematics
1 answer:
Olegator [25]3 years ago
4 0

i think systematic

could you answer my latest question

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Find the equation of a plane that is perpendicular to the vector −4i⃗ −4j⃗ −k⃗ and passing through the point (−2,−5,5)
vredina [299]

hello ....

the equation of a plane that is ;  ax+by+cz +d =0

the vector perpendicular to this plane is : V(a,b,c)

in this exercice ; a = -4  b= -4  c = -1

then: the equation of a plane that is ;  -4x-4y-z +d =0

but the plane  passing through the point (−2,−5,5) :

-4(-2)-4(-5)-(5) +d =0

23+d =0

d =-23

the equation of a plane is : -4x-4y-z-23 =0

5 0
4 years ago
Order the values from least to greatest
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3 tents 0.003 3 tines 100 3times 1000
6 0
3 years ago
How do you describe the transformation for each quadratic function
Aleks [24]
By turning it into a fraction
6 0
3 years ago
The complex polygon below represents the layout of a parking lot. Find the area of the parking lot in square meters.
alukav5142 [94]

Answer:

The area of the parking lot is: 144cm^2

Step-by-step explanation:

Given

See attachment for polygon

Required

The area of the parking lot

The attached plot has 6 congruent triangles with the following dimension;

Base = 6cm

Height = 8cm

Area = \frac{1}{2} * Base * Height

Area = \frac{1}{2} * 6cm * 8cm

Area = 24cm^2

The area of the 6 triangles is:

Area = 6 * Area of 1 triangle

Area = 6 * 24cm^2

Area = 144cm^2

8 0
3 years ago
A particle is moving with the given data. Find the position of the particle. v(t) = 1.5√t , s(4) = 14.
Leto [7]

Answer:

s(t) = t^{\frac{3}{2} } +6

Step-by-step explanation:

given that a particle is moving with velocity given by the function v(t)

We have to find the position of the particle

v(t) = 1.5\sqrt{t}

Since v is the derivative of s, we can find s by integrating v wrt t

s(t) = \int v(t) dt \\=\int 1.5\sqrt{t} dt\\=1.5 *\frac{2}{3} t^{\frac{3}{2} } +C

where C is the arbitrary constant of integration.

Use the fact s(4) = 14

s(t) = 1.5 *\frac{2}{3}* t^{\frac{3}{2} } +C\\s(4) = 1.5 *\frac{2}{3}*4^{\frac{3}{2} } +C=14\\8+C=14\\C = 6

So position of particle at time t is given by

s(t) = t^{\frac{3}{2} } +6

6 0
3 years ago
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