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faust18 [17]
1 year ago
15

Some of the following integers are prime. Compute the sum of the prime integers in the list. (a) 197 (b) 497 (c) 1111 (d) 2111 (

e) 2643 (f) 3599
Mathematics
1 answer:
spin [16.1K]1 year ago
4 0

The sum of the prime integers in the list is 10158.

<h3>What are Prime Numbers ?</h3>

The numbers that are divisible by 1 or itself is called a Prime Number.

The sum of two prime numbers is not a prime number

The given prime numbers are

197 , 497, 1111 ,2111 , 2643 , 3599

=197+ 497+1111+2111+2643+3599

= 10158

The sum of the prime integers in the list is 10158.

To know more about Prime Number

brainly.com/question/9315685

#SPJ1

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Answer:

15

Step-by-step explanation:

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3 0
2 years ago
A survey of 700 adults from a certain region​ asked, "What do you buy from your mobile​ device?" The results indicated that 59​%
Kryger [21]

Answer:

a) the test statistic z = 1.891

the null hypothesis accepted at 95% level of significance

b) the critical values of 95% level of significance is zα =1.96

c) 95% of confidence intervals are  (0.523 ,0.596)

Step-by-step explanation:

A survey of 700 adults from a certain region

Given sample sizes n_{1} = 400 and n_{2} = 300

Proportion of mean p_{1} = \frac{236}{400} = 0.59 and p_{2} = \frac{156}{300} = 0.52

<u>Null hypothesis H0</u> : assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

<u>Alternative hypothesis H1:</u>- p1 ≠ p2

a) The test statistic is

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }

where p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}  

on calculation we get   p = 0.56    

now q =1-p = 1-0.56=0.44

Z = \frac{p_{1} -p_{2} }{\sqrt{pq(\frac{1}{n_{1} }+\frac{1}{n_{2} )}  } }\\   =\frac{0.56-0.52}{\sqrt{0.56X0.44}(\frac{1}{400}+\frac{1}{300}   }

after calculation we get z = 1.891

b) The critical value at 95% confidence interval zα = 1.96 (from z-table)

The calculated z- value < the tabulated value

therefore the null hypothesis accepted

<u>conclusion</u>:-

assume that there is no significant difference between males and women reported they buy clothing from their mobile device

p1 = p2

c) <u>95% confidence intervals</u>

The confidence intervals are P± 1.96(√PQ/n)

we know that = p = \frac{n_{1}p_{1} +n_{2}p_{2} }{n_{1}+n_{2}}= \frac{400X0.59+300X0.52}{700}

after calculation we get P = 0.56 and Q =1-P =0.44

Confidence intervals are ( P- 1.96(√PQ/n), P+ 1.96(√PQ/n))

now substitute values , we get

( 0.56- 1.96(√0.56X0.44/700), 0.56+ 1.96(0.56X0.44/700))

on simplification we get (0.523 ,0.596)

Therefore the population proportion (0.56) lies in between the 95% of <u>confidence intervals  (0.523 ,0.596)</u>

<u></u>

3 0
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The high school leadership team is having a car wash. They charge $5.50 for large cars and $4.00 for small cars . They had a suc
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Answer: 56 large cars and 86 small cars.

Step-by-step explanation:

Let's call:

l: the number of large cars.

s: the number of small cars.

Then, you can set up the following system of equations:

\left \{ {{l+s=142} \atop {5.50l+4.0s=652.50}} \right.

You can use the Elimination Method:

- Multiply the first equation by -4.0

- Add both equations.

- Solve for l.

\left \{ {{-4.0l-4.0s=-568} \atop {5.50l+4.0s=652.50}} \right.\\--------\\1.5l=84.5

l≈56

Substitute l=56 into one of the original equations and solve for <em>s:</em>

<em> </em>56+s=142\\s=142-56\\s=86

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Answer:

Done below!

Step-by-step explanation:

(x - root)

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Answer:

A

Step-by-step explanation:

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