What number, when five is subtracted from it equals twelve
Answer:
Step-by-step explanation:
because both equations do not have matching numbers for the x or y variable, and both equations are positive you are going to have to multiply each equation by a number so that there will be at least one variable with the same number but with opposite signs.
it does not matter which variable you choose.
lets use y because 2 and 3 are smaller then 2 and 5.
so lets multiply the first equation by 2 in order to get y equal to 6.
2(2x)+2(3y)=(2)6
(do not forget to multiply what the equation is equal to also)
4x+6y=12
now for the second equation we need y to equal negative 6
-3(5x)+-3(2y)=-3(4)
-15x-6y=-12
now lets put the 2 new equations next to each other and see what we can cancel out
4x+6y=12
-15x-6y=-12
-11x=0
x=0
now plug 0 in for x and solve for y (it does not matter which of the 4 equations you choose to solve.
2(0)+3y=6
3y=6
y=2
so your answer is x=0, y=2
Answer:
if you mean cubed its 125 but if you mean squared its 25
Step-by-step explanation:
Answer:
$968
Step-by-step explanation:
x= the money John originally had in his savings account
The statement says that John spent $88 on a radio and 1/4 of what was left on presents for his friends. This means that the remaining money is 3/4 of the total amount minus the money spent on the radio:
3/4(x-88)
Then, it says that of the money remaining, John put 4/11 into a checking account and the last remaining $420 was left to charity. Since, he spent 4/11 of the remining 3/4(x-88), the remaining is 7/11 of that and that remaining is equal to $420 that was the money left at the end:
7/11(3/4(x-88))= 420
21/44(x-88)=420
21/44x-42=420
21/44x=462
x=968
According to this, the money that John originally had in his savings account was $968.
He spent $88 on a radio: 968-88= 880
1/4 of what was left on presents for his friends: 880/4= 220
880-220=660
Of the money remaining, John put 4/11 into a checking account: 660*(4/11)=240
the last remaining $420 was left to charity: 660-240= 420
Answer:
.
Step-by-step explanation:
Let 
and 
denote the two endpoints.
The formula for the midpoint of these two points would be:
.
(Similar to taking the average of each coordinate.)
In this question, it is given that 
whereas 
. Substitute these two values into the expression for the coordinate of the midpoint:
-coordinate of the midpoint: 
.
-coordinate of the midpoint: 
.
Solve these two equations for 
and 
: 
whereas 
.
Hence, the coordinate of the other point would be .
