Explain what a scatterplot is please and show and example

Mathematics

1 answer:

Kazeer [188]3 years ago

6 0

A scatter plot uses dots to represent values for two different variables, one is plotted on the x-axis, while the other is on the y-axis.

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A circle has a sector with area 27 and central angle of 120

Alex_Xolod [135]

Answer:

81π

Step-by-step explanation:

-The sum of central angles in a circle add up to 360°.

-Let x be the area of the circle.

-Given the area of a 120° is 27π, the circles area can be calculated as:

$A=27\pi\\\\120\textdegree=27\pi\\360\textdegree=x\\\\\therefore x=\frac{360\textdegree\times 27\pi}{120\textdegree}\\\\=3\times 27\pi\\\\=81\pi$

Hence, the area of the circle is 81π

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3 years ago

A watering can dispenses water at the rate of 0.25 gallon per minute. The original volume of water in the can was 6 gallons. Whi

nydimaria [60]

I believe the answer should be A {(1, 6.0),(2, 5.75),(3, 5.50)}

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3 years ago

PLEASE HELP I WILL MARK BRAINLIEST!!!!!!!!!!!!!!!!!!!!

Aleks [24]

Y = 6
x = 7
It’s the answer

5 0

3 years ago

What is the volume of the composite figure shown? (Use 3.14 for π.)

Nimfa-mama [501]

$The\ volume\ of\ the\ cone:V_1=\frac{1}{3}\pi r^2 H\\(r-a\ radius;\ H-height)\\------------------\\r=7ft;\ H=7ft\\\\V_1=\frac{1}{3}\pi\cdot7^2\cdot7=\frac{1}{3}\pi\cdot343=\frac{343}{3}\pi\ (ft^2)\\-------------------\\The\ volume\ of\ the\ cylinder:V_2=\pi r^2 H\\(r-a\ radius;\ H-height)\\-------------------\\r=7ft;\ H=6ft\\\\V_2=\pi\cdot7^2\cdot6=294\pi\ (ft^3)\\------------------------\\The\ volume\ of\ the\ composite\ figure: V_F=V_1+V_2$

$V_F=\frac{343}{3}\pi+294\pi=\frac{343}{3}\pi+\frac{294\cdot3}{3}\pi=\frac{343}{3}\pi+\frac{882}{3}\pi=\boxed{\frac{1225}{3}\pi\ (ft^3)}\\\\\approx\frac{1225}{3}\cdot3.14}=\frac{3846.5}{3}\approx\boxed{1,282.17\ (ft^3)}\leftarrow answer$

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3 years ago

P is inversely proportional to the cube of (q-2) p=6 when q=3 find the value of p when q is 5

sveticcg [70]

$\bf \begin{array}{llllll}
\textit{something}&&\textit{varies inversely to}&\textit{something else}\\ \quad \\
\textit{something}&=&\cfrac{{{\textit{some value}}}}{}&\cfrac{}{\textit{something else}}\\ \quad \\
y&=&\cfrac{{{\textit{k}}}}{}&\cfrac{}{x}
\\
&&y=\cfrac{{{ k}}}{x}
\end{array}\\\\
-----------------------------\\\\
\textit{p is inversely proportional to the cube of (q-2)}\implies p=\cfrac{k}{(q-2)^3}
\\\\\\
now \quad 
\begin{cases}
p=6\\
q=3
\end{cases}\implies 6=\cfrac{k}{(3-2)^3}$

solve for "k", to find k or the "constant of variation"

then plug k's value back to $\bf p=\cfrac{k}{(q-2)^3}$

now.... what is "p" when q = 5? well, just set "q" to 5 on the right-hand-side, and simplify, to see what "p" is

4 0

3 years ago