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3 years ago

Help me real quick. Its a times test

Mathematics

1 answer:

jenyasd209 [6]3 years ago

4 0

The equation that is equivalent to the given logarithmic equation is 3² = x + 5. The correct option is the third option 3² = x + 5

<h3>Logarithmic equations</h3>

From the question, we are to determine the equation that is equivalent to the given logarithmic equation

The given logarithmic equation is

$log_{3}(x+5) = 2$

From one of the laws of logarithm

If $log_{x}(y) = z$

Then,

$y = x^{z}$

Thus, $log_{3}(x+5) = 2$ becomes

$x+5 = 3^{2}$

∴ $3^{2} = x+5$

Hence, the equation that is equivalent to the given logarithmic equation is 3²= x + 5. The correct option is the third option 3² = x + 5

Learn more on Logarithmic equations here: brainly.com/question/23268551

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Drag each description to the correct location on the table. Each description can be used more than once.

Daniel [21]

Answer:

-6 - x^5+3x^2 is cubic, and trinomial

5x^3 - 8x is cubic, and binomial

1/3x^4 is quartic, and monomial

6/7x + 1 is linear, and binomial

-0.7x^2 is quadratic, and monomial

Step-by-step explanation:

Monomial is 1 term

Binomial is 2 terms

Trinomial is 3 terms

- Exponents don't count as terms btw

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3 years ago

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The circle above has a radius of 6 cm. What is the area of the circle? Use = 3.14.

nadya68 [22]

Answer:

Step-by-step explanation:

Using: A=πr squared, u do 3.14 times 6 squared, which gives u: 113.04!!

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3 years ago

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Explain the difference between linear, exponential, and quadratic functions in terms of their graphs, their patterns, and their

Kipish [7]

Answer:

Quadratic functions are those where their rate of change changes at a constant rate. Exponential functions are those where their rate of change is proportional to itself.

An example of a quadratic function would be the shape that a ball makes when you throw it. Gravity causes a constant acceleration, the ball slows down as it is moving up, and then it speeds up as it comes down.

An example of an exponential function would be the population of a bacterium as long as there is enough space and nutrients or how your money grows with compound interest in a bank.

A quadratic function is one in the form

f(x)=ax2+bx+c

It’s rate of change (first derivative) is linear.

f′(x)=2ax+b

The rate of the rate of change (second derivative) is constant.

f′′(x)=2a

Quadratics are then the solutions to the differential equation

f′′=C

An exponential function is one in the following form.

g(x)=Aekx

It’s rate of change is another exponential function.

g′(x)=Akekx

So exponentials are the solutions to the differential equation

g′=kg

Step-by-step explanation:

Yes. : )

8 0

3 years ago

The formula for a buffer solution contains 1.24% w/v of boric acid. How many milli-liters of a 5% w/v boric acid solution should

Oksanka [162]

Answer: 248mL

Step-by-step explanation:

Given:

Concentration of buffer solution Cs = 1.24%w/v of boric acid

Concentration of boric acid solution Cb = 5 % w/v boric acid

For 1 liter of buffer solution, the weight of boric acid needed is:

mb = 1 × 1.24 = 1.24 unit weight

mb = Cb × Vb .....1

Cb = concentration of boric acid solution.

Vb = volume of boric acid solution needed.

mb = weight of boric acid needed.

From equation 1.

Vb = mb/Cb

Vb = 1.24/5

Vb = 0.248L

Vb = 248mL

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3 years ago

Solve x^2=2x+3 by factoring

solong [7]

The solution is x = 1 and x = -3

<em><u>Solution:</u></em>

Given that we have to solve the given equation by factoring

Given equation is:

$x^2=2x + 3\\\\x^2 - 2x - 3 = 0$

$\text{Consider the form } x^2+bx+c$

Find a pair of integers whose product is c and and whose sum is b

$\text{Compare } x^2-2x-3 = 0 \text{ with } x^2+bx +c\\\\\text{We get } b = -2 \text{ and } c = -3$

Now find, a pair of integers whose sum is -2 and product is -3

The integers that satisfies this condition is -1 and 3

When we add - 1 and 3 we get 2

When multiply -1 and 3 we get -3

Thus the pair of integers are -1 and 3

Write the factored form using these integers.

$(x-1)(x+3) = 0$

The Zero Product Property states that if ab = 0, then either a = 0 or b = 0, or both a and b are 0

Set the factors equal to 0

$x - 1 = 0 \text{ and } x + 3 = 0$

x = 1 and x = -3

Thus the solution is x = 1 and x = -3

4 0

3 years ago