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tensa zangetsu [6.8K]
2 years ago
10

Multiply:(x+y)by (x+y)a+b by a^2-b^2(a+5) by (a^2-2a-3)(a^2-ab+b^3) by (a+b)​

Mathematics
1 answer:
Law Incorporation [45]2 years ago
7 0

Answer:

Multiply:

(x+y)by (x+y)

: \implies(x + y)(x + y)

: \implies \: x(x + y) + y(x + y)

: \implies {x}^{2}  + xy + xy +  {y}^{2}

: \implies{x}^{2}  + 2xy +  {y}^{2}

Multiply:

a+b \:  by  \: a^2-b^2

: \implies( {a}^{2}  +  {b}^{2} ) \times (a + b)

: \implies \:  {a}^{2} (a + b) -  {b}^{2} (a + b)

: \implies \:  {a}^{3}  +  {a}^{2} b -  {ab}^{2} -  {b}^{3}

Multiply:

(a+5) by (a^2-2a-3)

: \implies{(a + 5) \times ( {a}^{2} - 2a - 3) }

: \implies \: a({a}^{2} - 2a - 3) + 5( {a}^{2} - 2a - 3)

: \implies(a \times  {a}^{2}  - a \times 2a - a \times 3) + (5 \times  {a}^{2}  - 5 \times 2a - 5 \times 3)

: \implies{a}^{3} -  {2a}^{2} - 3a + 5 {a}^{2}   - 10a - 15

: \implies{ {a}^{3} +  {3a}^{2}   - 13a - 15}

Multiply:

(a^2-ab+b^3) by (a+b)

: \implies{(a + b) \times ( {a}^{2}  - ab +  {b}^{3} )}

: \implies \: a( {a}^{2} - ab +  {b}^{3}) + b( {a}^{2}  - ab +   {b}^{3}  )

: \implies {a}^{3} -  {a}^{2} b + a {b}^{3}  + {a^2b} -  {ab}^{2}  +  {b}^{4}

: \implies{ {a}^{3}+ab^3 - ab^2+ {b}^{4}  }

Step-by-step explanation:

\blue{ \frak{Seolle_{aph.rodite}}}

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Step-by-step explanation:

To find the y- intercept let x = 0 in the function

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