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xxTIMURxx [149]
2 years ago
13

Solve pls brainliest

Mathematics
1 answer:
WARRIOR [948]2 years ago
4 0

Step-by-step explanation:

please mark me as brainlest

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5x + y = 6 5x + 3y = -4 The y-coordinate of the solution to the system shown is _____. -5 -1 1
anzhelika [568]
5x +y = 6
5x + 3y = -4 
multiply top equation by -1 and bottom by 1
-5x -y = -6
5x+3y = -4
solve and get 
2y = -10
y = -10/2
y = -5 
answer is -5
8 0
3 years ago
Maren is buying carpet for her rectangular living room. The room is 4.8 yd wide and 5.2 yd long.
levacccp [35]
4.8×5.2=24.96 I hope my math is correct
8 0
3 years ago
Read 2 more answers
La un concurs, se acordă 10 puncte pentru o problema rezolvată corect si se scad 2 puncte
mylen [45]

Answer:

2 wrongly solutions and 18 right solutions

Step-by-step explanation:

The computation is shown below:

= 20 (problems) × 10 (points)

= 200 points

And it received 176 points

So the difference is of

= 200 - 176

= 24

In the case of wrong solution, the points that are lost is

=  10 + 2

= 12

Now the solutions done wrongly is

= 24 ÷ 12

= 2

And, the solutions does rightly is

= 20 - 2

= 18

6 0
3 years ago
Which decimal is equivalent to<br> -35?
Finger [1]

Answer:

-35.0

Step-by-step explanation:

6 0
4 years ago
Read 2 more answers
X ^ (2) y '' - 7xy '+ 16y = 0, y1 = x ^ 4
nignag [31]
Standard reduction of order procedure: suppose there is a second solution of the form y_2(x)=v(x)y_1(x), which has derivatives

y_2=vx^4
{y_2}'=v'x^4+4vx^3
{y_2}''=v''x^4+8v'x^3+12vx^2

Substitute these terms into the ODE:

x^2(v''x^4+8v'x^3+12vx^2)-7x(v'x^4+4vx^3)+16vx^4=0
v''x^6+8v'x^5+12vx^4-7v'x^5-28vx^4+16vx^4=0
v''x^6+v'x^5=0

and replacing v'=w, we have an ODE linear in w:

w'x^6+wx^5=0

Divide both sides by x^5, giving

w'x+w=0

and noting that the left hand side is a derivative of a product, namely

\dfrac{\mathrm d}{\mathrm dx}[wx]=0

we can then integrate both sides to obtain

wx=C_1
w=\dfrac{C_1}x

Solve for v:

v'=\dfrac{C_1}x
v=C_1\ln|x|+C_2

Now

y=C_1x^4\ln|x|+C_2x^4

where the second term is already accounted for by y_1, which means y_2=x^4\ln x, and the above is the general solution for the ODE.
4 0
3 years ago
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