Ask question

Ask question

All categories

2 years ago

10

5. x = 5,- ²/3, √2 help pls

1 answer:

Marianna [84]2 years ago

6 0

Answer: 2. 5. f(x)=x²-5; vertically stretched by a factor of 4, followed by a translation 3 units to the right. 4(x²-5). 4((x-3)²-5) g(x)= 4(x-3)²-20.

Step-by-step explanation:

You might be interested in

Which graph could represent a car that begins by increasing its speed, then travels at a constant speed, and then decreases its

liraira [26]

Answer:

videsi yatra vivaran ka

3 0

2 years ago

Read 2 more answers

This is an urgent message, help me and get 30 points and brainiest answer!

GaryK [48]

The initial value is where the line intersects the y-axis. So, this does it at y = 2. The graph has a slope (rate of change) of 1, because for every x-value, the y-value goes up by exactly 1. So, the answer is C.

4 0

3 years ago

Read 2 more answers

Verify each trigonometric equation by substituting identities to match the right hand side of the equation to the left hand side

lorasvet [3.4K]

Answer:

Step-by-step explanation:

1.

cot x sec⁴ x = cot x+2 tan x +tan³x

L.H.S = cot x sec⁴x

=cot x (sec²x)²

=cot x (1+tan²x)² [ ∵ sec²x=1+tan²x]

= cot x(1+ 2 tan²x +tan⁴x)

=cot x+ 2 cot x tan²x+cot x tan⁴x

=cot x +2 tan x + tan³x [ ∵cot x tan x $=\frac{ \textrm{tan x }}{\textrm{tan x}}$ =1]

=R.H.S

2.

(sin x)(tan x cos x - cot x cos x)=1-2 cos²x

L.H.S =(sin x)(tan x cos x - cot x cos x)

= sin x tan x cos x - sin x cot x cos x

$=\textrm{sin x cos x }\times\frac{\textrm{sin x}}{\textrm{cos x} } - \textrm{sinx}\times\frac{\textrm{cos x}}{\textrm{sin x}}\times \textrm{cos x}$

= sin²x -cos²x

=1-cos²x-cos²x

=1-2 cos²x

=R.H.S

3.

1+ sec²x sin²x =sec²x

L.H.S =1+ sec²x sin²x

= $1+\frac{{sin^2x}}{cos^2x}$ [ $\textrm{sec x}=\frac{1}{\textrm{cos x}}$ ]

=1+tan²x $[\frac{\textrm{sin x}}{\textrm{cos x}} = \textrm{tan x}]$

=sec²x

=R.H.S

4.

$\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}} = \textrm{2 csc x}$

L.H.S= $\frac{\textrm{sinx}}{\textrm{1-cos x}} +\frac{\textrm{sinx}}{\textrm{1+cos x}}$

$=\frac{\textrm{sinx(1+cos x)+{\textrm{sinx(1-cos x)}}}}{\textrm{(1-cos x)\textrm{(1+cos x})}}$

$=\frac{\textrm{sinx+sin xcos x+{\textrm{sinx-sin xcos x}}}}{{(1-cos ^2x)}}$

$=\frac{\textrm{2sin x}}{sin^2 x}$

= 2 csc x

= R.H.S

5.

-tan²x + sec²x=1

L.H.S=-tan²x + sec²x

= sec²x-tan²x

= $\frac{1}{cos^2x} -\frac{sin^2x}{cos^2x}$

$=\frac{1- sin^2x}{cos^2x}$

$=\frac{cos^2x}{cos^2x}$

=1

8 0

4 years ago

If ∆ABC ≅ ∆PQR ,then side AB corresponds to -------------------

serg [7]

By direct correspondence AB = PQ

7 0

3 years ago

Read 2 more answers

How much money would be collected if 24 sweatshirts were sold?

Rudiy27

Answer:

it depends how much one would cost

Step-by-step explanation:

and when u know how much one costs u can multiply it by 24 :)

8 0

4 years ago