Question

Passes through (6,-3) and perpendicular to the line whose equation is y=1/3x +5

Answer 1

Answer:

y = -3x + 15

Step-by-step explanation:

The general structure for an equation is slope-intercept form is:

y = mx + b

In this form, "m" is the slope and "b" is the y-intercept.

The slope of a perpendicular line is the opposite signed, reciprocal of the original line's slope. So, if the slope in the original equation is (m = 1/3), the slope of the perpendicular line is (m = -3).

Now that we know the slope, we can use the "x" and "y" values from the given point to find the value of "b".

y = mx + b                           <----- Slope-intercept form

y = -3x + b                           <----- Plug -3 into m

-3 = -3(6) + b                       <----- Plug in "x" and "y" values from point (6,-3)

-3 = -18 + b                          <----- Multiply -3 and 6

15 = b                                  <----- Add 18 to both sides

Since we identified that m = -3 and b = 15, you can substitute these values into the general equation to find the equation of the new line.

y = -3x + 15