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ad-work [718]
3 years ago
12

Answer the following questions CORRECTLY I will know if this is wrong. I WILL REPORT ANY INCORRECT ANSWERS!

Mathematics
2 answers:
Goshia [24]3 years ago
6 0

remember, for |a|>b, solve a>b or a<-b (or means that the solution has to satisfy at least 1 of those inequalities)


|-4x+24|-4>36

add 4 to both sides

|-4x+24|>40

apply rule

-4x+24>40 or -4x+24<-40

minus 24 from everybody

-4x>16 or -4x<-64

divide everybody by -4, also flip the sign of the inequality since you are dividing by a negative

x<-4 or x>16 is the area where permissible values of x are

charle [14.2K]3 years ago
5 0

Answer by JKismyhusbandbae: x < - 4 or x > 16

(Work is in picture)

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To find the point of intersection, you have to set them equal to each other.

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simplify the following expression: (x+7/4x) + (5/x-8) I also attached a photo of the problem if you get confused on how I typed
Gnoma [55]

Answer:

\frac{x^{2}  + 19x - 56}{4 {x}^{2}   - 32x}

Step-by-step explanation:

Start by making the denominators of both fraction the same. This can be done by multiplying one fraction's denominator by the other.

After simplifying and combining the two fractions together, check if the numerator can be factorised such that there is a common factor in the denominator and numerator. In this case, the numerator cannot be factorised.

Lastly, expand the denominator.

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=  \frac{(x + 7)(x - 8)}{4x(x - 8)}  +  \frac{5(4x)}{4x(x - 8)}

=  \frac{x(x) + x( - 8) + 7(x) + 7( - 8) + 20x}{4x(x - 8)}

=  \frac{ {x}^{2} - 8x + 7x - 56 + 20x }{4x(x - 8)}

=  \frac{ {x}^{2}  + 19x - 56}{4x(x - 8)}

=  \frac{ {x}^{2}  + 19x - 56}{4 {x}^{2}  -  32x}

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2 years ago
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