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Musya8 [376]
2 years ago
6

On the dance decoration committee, there are 6 seniors, 4 juniors, and 5 sophomores. Of these learners, 4 seniors, 3 juniors, an

d 3 sophomores are male. One learner is picked at random to present the decoration plans to the principal.
What is the probability that the learner is a senior or a male?
Mathematics
1 answer:
AfilCa [17]2 years ago
4 0

Using it's concept, it is found that there is a 0.8 = 80% probability that the learner is a senior or a male.

<h3>What is a probability?</h3>

A probability is given by the <u>number of desired outcomes divided by the number of total outcomes</u>.

In this problem, there is a total of 6 + 4 + 5 = 15 students. Of those, there are 6 seniors, and 6 male non-seniors, hence there are 12 desired outcomes, and the probability is given by:

p = 12/15 = 0.8 = 80%.

More can be learned about probabilities at brainly.com/question/14398287

#SPJ1

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Which congruence theorem can be used to prove △WXS ≅ △YZS? Triangles W X S and Y Z S are connected at point S. Angles W X S and
iVinArrow [24]

Point S makes the two connected angles the same. They both have right angles.

And one side of each is congruent.

This means you know 2 angles are the same and one side is the same.

You would use ASA (Angle, Side, Angle)

3 0
3 years ago
Read 2 more answers
You will need to flip the inequality sign when you subtract 4 from each side in the inequality + 4 &lt; 9. True False
Len [333]
False, you only flip the inequality if you divide out a negative.
6 0
4 years ago
The length and width of a book cover are 22.2 centimeters and 12 centimeters respectively. The actual length (and width) can be
expeople1 [14]

Part (a)

The length is supposed to be 22.2 cm, but it could be 0.3 cm less

So 22.2 - 0.3 = 21.9 cm is the smallest value for the length. This is the lower bound of the length.

The upper bound is 22.2 + 0.3 = 22.5 cm as it is the largest the length can get.

-------------

Use this for the width as well

The width is supposed to be 12 cm, but it could be as small as 12-0.3 = 11.7 cm and as large as 12+0.3 = 12.3 cm

-------------

<h3>Answers:</h3>
  • smallest length = 21.9 cm
  • largest length = 22.5 cm
  • smallest width = 11.7 cm
  • largest width = 12.3 cm

============================================

Part (b)

Use the smallest length and width to get the smallest possible area

smallest area = (smallest width)*(smallest length) = 11.7*21.9 = 256.23

-------------

Repeat the same idea but for the largest length and width to get the largest possible area

largest area = (largest width)*(largest length) = 12.3*22.5 = 276.75

-------------

<h3>Answers:</h3>
  • smallest area = 256.23 square cm
  • largest area = 276.75 square cm
7 0
3 years ago
Convert the line integral to an ordinary integral with respect to the parameter and evaluate it. modifyingbelow integral from no
vovangra [49]

Parameterize C by

\vec r(t)=(1-t)(0,0,0)+t(1,3,6)=(t,3t,6t)

with 0\le t\le1. Then the line integral is

\displaystyle\int_Cxyz\,\mathrm dS=\int_0^1x(t)y(t)z(t)\left\|\frac{\mathrm d\vec r}{\mathrm dt}\right\|\,\mathrm dt

=\displaystyle18\sqrt{91}\int_0^1t^3\,\mathrm dt=\boxed{\frac{9\sqrt{91}}2}

8 0
4 years ago
Please guys help me out with this
Kisachek [45]

When you have a negative exponent, you move the variable with the negative exponent to the other side of the fraction to make the exponent positive.

For example:

x^{-2} or \frac{x^{-2}}{1} =\frac{1}{x^2}

\frac{1}{2y^{-3}} =\frac{y^3}{2}  (you don't move the "2" because "2" has an exponent of 1, only "y" has the negative exponent)

\frac{5^{-2}}{y}=\frac{1}{(5^2)y} =\frac{1}{25y}

When you multiply a variable with an exponent by a variable with an exponent, you add the exponents together. (But you can only combine the exponents when the variables are the same)

x^2(y^3)=x^2y^3     (You can't combine them because they have different variables of x and y)

x^3(x^5)=x^{(3+5)}=x^8

y^3(y^2)=y^{(3+2)}=y^5

There's two ways you can do this. Either by first making all the exponents positive then do subtraction, or multiply them then make all the exponents positive. I'm doing the 2nd way.

2w^7u^{-2}w^{-6}*9y^{-6}*2y^9u  You can combine the numbers 2 x 9 x 2 = 36

36w^7u^{-2}w^{-6}y^{-6}y^9u    Now multiply the terms with the same variables

36(w^{7+(-6)})(u^{(-2+1)})(y^{(-6+9)})    

36(w^1)(u^{-1})(y^3)     Now make all the exponents positive

\frac{36wy^3}{u}

If you were to do subtraction, here is what you need to know:

When you divide a variable with an exponent by a variable with an exponent, you subtract the exponents together. (Reminder: they have to be the same variable in order to combine the exponents)

For example:

\frac{x^3}{x^2} =x^{(3-2)}=x^1   or  x

\frac{y^2}{y^4} =y^{(2-4)}=y^{-2}=\frac{1}{y^2}

7 0
3 years ago
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