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kumpel [21]
4 years ago
14

What is the phase shift of a periodic function?

Mathematics
2 answers:
LekaFEV [45]4 years ago
5 0

Answer and Explanation :

To find : What is the phase shift of a periodic function?

Solution :

The Phase shift is defined as a horizontal shift in a function in any direction.

Horizontal stretches will change the period of the function and that horizontal shift is called a phase shift or the amount of shift in a wave horizontally.

The phase shift is measured in degrees.

Refer the attached figure below for the pictorial representation of teh phase shift.

In the figure, \frac{\pi }{2} \text{ to } \pi is showing the phase shift.

Example - Taking a general example of sin function

y = A \sin(B(x + C)) + D

In this the phase shift is at C (positive is to the left).

vampirchik [111]4 years ago
4 0

a change in the phase of a waveform

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The sum of two consecutive integers is at least negative fifteen. What are the smallest values of consecutive integers that will
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Hello,

Your answer would be:

Let x = the first integer
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x + (x + 1) ≥ -15
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Does 24, 7, and 26 form a right triangle
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3 years ago
An entomologist can model the number of mosquitos in a forest as a function of
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The interpretation of the point of intersection of the curves is (c) they give a solution to the equation 5x - x^2 = 3x - 0.5x^2

<h3>How to interpret the points of intersection?</h3>

The graph of the two functions alongside their equations are the given parameters of this question

The functions are given as:

f(x) = 5x - x^2

g(x) = 3x - 0.5x^2

When the graphs of two curves or lines intersect on a coordinate plane, it means that the point of intersection represents where the graphs have equal value

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Substitute the known values in the above equation

5x - x^2 = 3x - 0.5x^2

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6 0
2 years ago
Which expression is equivalent to \root(3)(x^(5)y)
san4es73 [151]

Answer:

\sqrt[3]{x^{5}y} = x^{\frac{5}{3}}y^\frac{1}{3}

Step-by-step explanation:

Given

\sqrt[3]{x^{5}y}

Required

The equivalent expression

We have:

\sqrt[3]{x^{5}y}

Rewrite as an exponent

\sqrt[3]{x^{5}y} = (x^{5}y)^\frac{1}{3}

Open bracket

\sqrt[3]{x^{5}y} = x^{5*\frac{1}{3}}y^\frac{1}{3}

\sqrt[3]{x^{5}y} = x^{\frac{5}{3}}y^\frac{1}{3}

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3 years ago
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