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velikii [3]
2 years ago
9

Why is the engineering design process important to the customer?

Computers and Technology
1 answer:
Ket [755]2 years ago
8 0

The engineering design process important to the customer layout system permits things: A shared technique on a way to discover and remedy problems. A framework to assess ideas, tell priorities and save you myopic paintings.

<h3>What is the maximum vital step withinside the engineering layout system?</h3>

The first step withinside the engineering layout system is to outline the trouble that you are solving. This step is the maximum vital, as a defective know-how of the trouble handy ends in layout failures. Engineers paintings to discover the foundation trouble via way of means of opposite engineering the signs and symptoms they perceive.

The engineering layout system, via way of means of definition, is a sequence of steps that engineers use to discover an option to a trouble. These steps include: defining the trouble, brainstorming solutions, designing and constructing a prototype of the solution, trying out the solution, and enhancing it.

Read more bout the engineering :

brainly.com/question/17169621

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How do you select a single cell, a single column, a single
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Read 2 more answers
The 7-bit ASCII code for the character ‘&amp;’ is: 0100110 An odd parity check bit is now added to this code so 8 bits are trans
Alex787 [66]

Answer

First part:

The transmitted 8-bit sequence for ASCII character '&' with odd parity will be 00100110. Here leftmost bit is odd parity bit.

Second part:

The invalid bit sequence are option a. 01001000 and d. 11100111

Explanation:

Explanation for first part:

In odd parity, check bit of either 0 or 1 is added to the binary number as leftmost bit for making the number of 1s in binary number odd.

If there are even number of 1s present in the original number then 1 is added as leftmost bit to make total number of 1s odd.

If there are odd number of 1s present in the original number then 0 is added as leftmost bit to keep the total number of 1s odd.  

Explanation for second part:

A valid odd parity bit sequence will always have odd number of 1s.

Since in option a and d,  total number of 1s are 2 and 6 i.e. even number. Therefore they are invalid odd parity check bit sequences.

And since in option b and c, total number of 1s are 5 and 7 i.e. odd numbers respectively. Therefore they are valid odd parity check bit sequences.

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