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beks73 [17]
2 years ago
5

A winery has a vat with two pipes leading to it. The inlet pipe can fill the vat in 3 ​hours, while the outlet pipe can empty it

in 10 hours. How long will it take to fill the vat if both pipes are left​ open?
Mathematics
1 answer:
leva [86]2 years ago
5 0

The time it will take to fill the vat if both pipes are left open is = 4.3 hours

<h3>Calculation of time taken to fill vat</h3>

The number of pipes a vat has = 2

The time it takes the inlet pipe to fill the vat = 3hrs

The time it takes the outlet pipe to empty the vat= 10hrs

Therefore, the time it will take to fill the vat if both pipes are left open is;

1/t = 1/3-1/10

1/t = 7/30

Make t the subject of formula,

t = 30/7

t= 4.3 hours

Learn more about hours here:

brainly.com/question/291457

#SPJ1

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(a)

The information provided is:

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Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

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          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

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(b)

Now it is provided that:

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Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

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Thus, the sample sizes are 6666.

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