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Marta_Voda [28]
3 years ago
11

Which correlation coefficient would most likely show a weak negative association?

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
3 0
The correct answer would be B.-0.88
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What is the solution to the system graphed below?
IceJOKER [234]

Answer:

(-4,-1)

Step-by-step explanation:

If I am reading this question correctly, to find a solution to a graph you find the ordered pair of where the two lines intersect.

these two lines intersect at, (-4, -1)

4 0
3 years ago
-1/5, 5/6,1.3,1 1/3, 5/3 -4/3 least to greatest
Sergeeva-Olga [200]
I DK I DK I DK I DK but maybe it’s already in that order
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3 years ago
Read 2 more answers
you need to answer A and B!!! PLEASE HELP
4vir4ik [10]

Answer:

13x+14

Step-by-step explanation:

because the original equation would be 5x(2)+3x+7(2) simplified would be 13x+14

3 0
3 years ago
WILL GIVE BRAINLYIST
marysya [2.9K]

Answer:

64 degrees

Step-by-step explanation:

Since the triangles are similar they have the same angle measures

\frac{PR}{PQ} =\frac{SU}{ST}          \frac{21}{14}= \frac{6}{4}

∠P = ∠S ∠R =∠U ∠Q=∠T

We know 2 of the angle measures: ∠S and ∠R, and since they are similar we know ∠P and ∠U

In triangles the sum of all angle measures is always 180 degrees, so we can solve for ∠Q with this formula

A+B+C=180

46+70+C+180

116+C=180

subtract 116 from both sides

C=64

Therefore ∠Q is equal to 64 degrees

3 0
3 years ago
Find the distance between points P(5, 1) and Q(3, 4) to the nearest tenth
pav-90 [236]

Answer:

\sqrt{13} units

Step-by-step explanation:

The distance formula is d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2} where d is the distance between points (x_1,y_1) and (x_2,y_2). Let (x_1,y_1)\rightarrow(5,1) and (x_2,y_2)\rightarrow(3,4), thus:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\\\d=\sqrt{(3-5)^2+(4-1)^2}\\\\d=\sqrt{(-2)^2+(3)^2}\\\\d=\sqrt{4+9}\\\\d=\sqrt{13}

Therefore, the distance between points P(5,1) and Q(3,4) is \sqrt{13} units.

8 0
3 years ago
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