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Romashka-Z-Leto [24]
2 years ago
7

Sin²A-cos²A=2sin²A-1​

Mathematics
2 answers:
xz_007 [3.2K]2 years ago
8 0

\sin^2\alpha-\cos^2\alpha=2\sin^2\alpha-1\\\sin^2\alpha+\cos^2\alpha=1

This is the Pythagorean identity, therefore \alpha\in\mathbb{R}.

Inga [223]2 years ago
7 0

Step-by-step explanation:

please mark me as brainlest

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