2 years ago

Sin²A-cos²A=2sin²A-1

Mathematics

2 answers:

xz_007 [3.2K]2 years ago

8 0

$\sin^2\alpha-\cos^2\alpha=2\sin^2\alpha-1\\\sin^2\alpha+\cos^2\alpha=1$

This is the Pythagorean identity, therefore $\alpha\in\mathbb{R}$ .

Inga [223]2 years ago

7 0

Step-by-step explanation:

please mark me as brainlest

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Sin²A-cos²A=2sin²A-1​

Sin²A-cos²A=2sin²A-1