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max2010maxim [7]

3 years ago

10

If one root is the square root of the other in the equation 8 + mx + 27x^2 = 0, find the value of m

1 answer:

ICE Princess25 [194]3 years ago

6 0

Answer:

Step-by-step explanation:

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Y= -27(x+4)³+1 the real zero(s) is (are)

rjkz [21]

$\bf y=-27(x+4)^3+1\implies 0=-27(x+4)^3+1
\\\\\\
-1=-27(x+4)^3\implies \cfrac{-1}{-27}=(x+4)^3\implies \cfrac{1}{27}=(x+4)^3
\\\\\\
\sqrt[3]{\cfrac{1}{27}}=x+4\implies \cfrac{\sqrt[3]{1}}{\sqrt[3]{27}}=x+4\implies \cfrac{1}{3}=x+4\implies \cfrac{1}{3}-4=x
\\\\\\
-\cfrac{11}{3}=x$

4 0

3 years ago

20 points brainlist thanks

Fed [463]

Answer:

The answer Is 10.20

Step-by-step explanation:

d = \/(0-(-2))² + (-6-4)²

d = \/(0+2)² + (-10)²

d = \/(2² + 100)

d = \/(4+100)

d = \/104

d ~ 10,20

4 0

3 years ago

Read 2 more answers

Julio's wages vary directly as the number of hours that he works. if his wages for 5 hours are $29.75, how much will he earn for

OlgaM077 [116]

Answer:

$178.50

Step-by-step explanation:

Big brain go thinky-think.

6 0

3 years ago

I need answer please

ValentinkaMS [17]

Answer:

they are integers

Step-by-step explanation:

8 0

3 years ago

What is the slope intercept from of the equation of the line that that passes through the points (-3, 2) and (1, 5)

viva [34]

The slope-intercept form of a line:

$y=mx+b\\\\m=\dfrac{y_2-y_1}{x_2-x_1}\to slope\\\\b\to y-intercept$

We have:

$(-3,\ 2)\to x_1=-3,\ y_1=2\\(1,\ 5)\to x_2=1,\ y_2=5$

Substitute:

$m=\dfrac{5-2}{1-(-3)}=\dfrac{3}{4}$

$y=\dfrac{3}{4}x+b$

Put the values of coordinates of the point (1, 5) to the equation of a line:

$5=\dfrac{3}{4}(1)+b\\\\5=\dfrac{3}{4}+b\qquad|-\dfrac{3}{4}\\\\b=4\dfrac{1}{4}$

Answer: $y=\dfrac{3}{4}x+4\dfrac{1}{4}$

5 0

3 years ago