Question

(sin^2x) / (1-cosx) = (secx+1) / (secx)

Answer 1

The proof of the equation (sin²x) / (1-cosx) = (secx+1) / (secx) is given below.

What is trigonometry?

The connection between the lengths and angles of a triangular shape is the subject of trigonometry.

The equation is given below.

(sin²x) / (1-cosx) = (secx+1) / (secx)

Taking the left-hand side, then we have

⇒ [sin²x / (1 - cos x)] × [(1 + cos x) / (1 + cos x)]

⇒ [sin²x (1 + cos x)] / [1 - cos² x)]

⇒ [sin²x (1 + cos x)] / [sin² x)]

⇒ 1 + cos x

⇒ 1 + 1/sec x

⇒ (sec x + 1) / sec x = Right-hand side

More about the trigonometry link is given below.

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