Answer:
The score that cuts off the bottom 2.5% is 48.93.
Step-by-step explanation:
When the distribution is normal, we use the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this question, we have that:

What is the score that cuts off the bottom 2.5%
This is X when Z has a pvalue of 0.025, so X when Z = -1.96.




The score that cuts off the bottom 2.5% is 48.93.
Are u dumb or somthing????????
The angles in the triangles are the same, so you know the triangles are similar. Sides PQ and AB correspond as do sides PR and AC. Because the triangles are similar, you know that
PR/AC = PQ/AB
PR/24 = 5/20
Multiplying this equation by 24 gives
PR = 24*(5/20) = 6
The appropriate choice is ...
C. 6
Answer:
7x+72xy
Step-by-step explanation:
7x+8x(9y)=7x+72xy
Answer:
1/2 is the pre image for this