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Dennis_Churaev [7]
1 year ago
8

Write an expression for the perimeter of the triangle shown below:

Mathematics
1 answer:
anyanavicka [17]1 year ago
8 0

Answer:

5.5x + 9

Step-by-step explanation:

0.3x plus 24, 5x, and 0.2x minus 15

Expression:

This means that,

0.3x + 24 + 5x + 0.2x - 15

We know the perimeter of the triangle is,

  • P = a+b+c

Where a , b , c refers to the sides of that triangle.

So Just add them up:

  • 0.3x + 24 + 5x + 0.2x - 15
  • 0.3x+5x+0.2x + 24 - 15
  • 0.5x+5x + 9
  • 5.5x + 9

Hence,last choice is accurate.

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Which number is between 0.6 7/9
irakobra [83]
First we make the fractions homonym ( they must have the same denomitator)

0.6 = 6 / 10                                                  7/9

6/10 = 6 * 9 / 10 * 9 = 54 / 90                        7/9 = 7 * 10 / 9 * 10 = 70 / 90

The numbers which are between these numbers are ;

55 / 90 , 56 / 90 , 57 / 90 , 58 / 90 , 59 / 90, 60 / 90 , 61 / 90 , 62 / 90 , 63 / 90 , 64 / 90, 67 / 90 , 68 / 90 , 69 / 90

62 / 90 = 62 / 2 / 90 /2 =  31 / 45 

So the right answer is B.

Hope that helps :)
8 0
3 years ago
Which expression is equivalent to 4^6 ⋅ 4^−8? 1 over 4 to the 2nd power 1 over 4 to the 14th power 42 414
jarptica [38.1K]
4^6*4^-^8 = 4^6^+^-^8=4^-^2= \frac{1}{4^2} = \frac{1}{16}
4 0
3 years ago
Read 2 more answers
A new test to detect TB has been designed. It is estimated that 88% of people taking this test have the disease. The test detect
Elodia [21]

Answer:

Correct option: (a) 0.1452

Step-by-step explanation:

The new test designed for detecting TB is being analysed.

Denote the events as follows:

<em>D</em> = a person has the disease

<em>X</em> = the test is positive.

The information provided is:

P(D)=0.88\\P(X|D)=0.97\\P(X^{c}|D^{c})=0.99

Compute the probability that a person does not have the disease as follows:

P(D^{c})=1-P(D)=1-0.88=0.12

The probability of a person not having the disease is 0.12.

Compute the probability that a randomly selected person is tested negative but does have the disease as follows:

P(X^{c}\cap D)=P(X^{c}|D)P(D)\\=[1-P(X|D)]\times P(D)\\=[1-0.97]\times 0.88\\=0.03\times 0.88\\=0.0264

Compute the probability that a randomly selected person is tested negative but does not have the disease as follows:

P(X^{c}\cap D^{c})=P(X^{c}|D^{c})P(D^{c})\\=[1-P(X|D)]\times{1- P(D)]\\=0.99\times 0.12\\=0.1188

Compute the probability that a randomly selected person is tested negative  as follows:

P(X^{c})=P(X^{c}\cap D)+P(X^{c}\cap D^{c})

           =0.0264+0.1188\\=0.1452

Thus, the probability of the test indicating that the person does not have the disease is 0.1452.

4 0
3 years ago
Last one in math! Help Me
Andre45 [30]
I CALCULATED IT AND GOT
C) 4.29
3 0
3 years ago
Read 2 more answers
PLEASE HELP QUICK! I’ll give brainleist!!!
Fudgin [204]

1. set up the equation which makes these shapes equal, 1/2(2(x+1)) = 1x

2. solve, x+1=x, 1=0

3. since this is impossible, there is no solution and zero answers

5 0
3 years ago
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