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Marysya12 [62]
4 years ago
10

Pleaseee helppp!!! Need to pass this test!!!!

Mathematics
2 answers:
sweet-ann [11.9K]4 years ago
8 0

Answer:

2

Step-by-step explanation:

Andre45 [30]4 years ago
7 0

Answer: 2

Step-by-step explanation: These are similar trapezoids so you take 4 * 5 /10 = 2

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Sanjay needs 90 meters of fence to go around a rectangular garden.
Mademuasel [1]

To find the perimeter of a rectangle you can multiply the length by 2 and the width by 2, or you can add the four sides together.

The wrong equation is w + 3w = 90 because it only has one width and one length, which would be half the total perimeter.

5 0
3 years ago
In the figure, quadrilateral ABCD≅≅ quadrilateral LMNO. Find m. Only type the numerical amount.
Talja [164]
Using our congruence statement ABCD \cong LMNO, we know that corresponding angles match, so that means that \angle M \cong \angle B.  We know that m \angle B=131, so that means that m \angle M=131.  This gives us the equation 
<em /><em /><em>m</em> + 45 = 131
Subtract 45 from both sides to cancel it and we have 
<em>m</em> = 86.
7 0
3 years ago
If mZFBC = (10x – 9), mZCBE = (4x + 15),<br> find mZFBE.
erastovalidia [21]

Answer:

BEFmZ Is the answer i think

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
Evaluate 8-m/m+p3 when m=8 n=2 p=7
seropon [69]

Answer:

28

Step-by-step explanation:

8 - 8 / 8 + 7 *3

PEMDAS

8 - 1 * 7 - 3

8 - 1 + 21

28

3 0
3 years ago
Please put down the steps?
e-lub [12.9K]
The answer is:  " x = 0, 1 " .
__________________________________________
Explanation:
__________________________________________
Given:
__________________________________________
   " √(x + 1)  <span>− 1 = x "  ;   Solve for "x" ;

First, let us assume that "x </span>≥ -1 "
<span>
Add "1" to EACH SIDE of the equation:

 </span>→  √(x + 1)  − 1  + 1 = x + 1  ; 

to get:  

 →  √(x + 1)  = x + 1 .

Now, "square" EACH side of the equation:

 →  [√(x + 1) ]²  = (x + 1 )² ;

to get: 

   x + 1 = (x + 1)² 

↔  (x + 1)²  = (x + 1) .


Expand the "left-hand side" of the equation:

 → (x + 1)² = (x + 1)(x +1) ;

Note: (a+b)(c+d) = ac +ad + bc + bd ;

As such:  (x + 1)(x + 1) = (x*x) + (x*1) +(1(x) + (1*1) ;
                                   =  x² + 1x + 1x + 1 ; 
                                   =  x²  + 2x  +  1 ;

Now, substitute this "expanded" value, and bring down the "right-hand side" of the equation; and rewrite the equation:
__________________________________________
   " (x + 1)² = (x + 1)(x +1) " ; 

  →  Rewrite as:  " x² + 2x + 1 = x + 1 " ;

 Subtract "x" ;  and subtract "1" ; from EACH SIDE of the equation:

               →   x² + 2x + 1 - x - 1 = x + 1 - x - 1 ; 

to get:    →   x² <span>− x = 0  

Factor out an "x" on the "left-hand side" of the equation:
___________________________________________
         </span>x² − x = x(x − 1) ;

         →  x (x − 1) = 0 ;

We have:  "x" and "(x − 1)" ; when either of these two multiplicands are equal to zero, then the "right-hand side of the equation equals "zero" .

So, one value of "x" is "0" .

The other value for "x" ;

→  x − 1 = 0 ;

Add "1" to each side of the equation:

  → x − 1 + 1 = 0 + 1 ; 

 →  x = 1 ; 
__________________________________
So, the answers:

 " x = 0, 1 " .
_________________________________

4 0
4 years ago
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