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Stels [109]
2 years ago
8

Given that √5 = 2.24 and √50= 7.07 , find √500 and √0.5

Mathematics
1 answer:
sineoko [7]2 years ago
3 0

Answer:

see explanation

Step-by-step explanation:

using the rules of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

\sqrt{\frac{a}{b} } ⇔ \frac{\sqrt{a} }{\sqrt{b} }

then

\sqrt{500}

= \sqrt{100(5)}

= \sqrt{100} × \sqrt{5}

= 10 × 2.24

= 22.4

-------------------------------

\sqrt{0.5}

= \sqrt{\frac{50}{100} }

= \frac{\sqrt{50} }{\sqrt{100} }

= \frac{\sqrt{50} }{10}

= \frac{7.07}{10}

= 0.707

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Answer:

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Therefore, the length between points AB is

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Similarly, length BC is given by

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The perimeter is equal to;

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If the point D is moved up 2 units and left 1 unit we have

D' = x-1, y+2 where x and y are the coordinates of point D

D(4, -3) → D'((4-1), (-3+2)) = D'(3, -1)

The length D'A =  \sqrt{(7)^2+(0)^2} =  \sqrt{49} =7 units

The perimeter of polygon ABCD'

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= 4.472 + 4.123 + 5.385 + 7 = 20.980 units.

The area is given by the determinant of the 3 by 3 matrix using Cramer's Rule as follows

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