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pav-90 [236]
3 years ago
13

Is it possible to form a triangle with the given side lengths? 15 yd,16yd,30yd

Mathematics
2 answers:
lukranit [14]3 years ago
4 0

<u>Answer:</u>

<h2>Yes</h2>

<u>Explanation:</u>

15 < 16+30

16 < 15+30

30 < 16+15

Nana76 [90]3 years ago
3 0
Yes it is possible to form a trial for
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The equation of a circle is ​ (x−2)2+(y−16)2=169 ​ .
ss7ja [257]
Hello!

The radius is the square root of the number right to the equal sign.

In this case that number is 169.

The square root of 169 is 13.

Hope this helped!
7 0
3 years ago
Which of the following is an example of a function
kicyunya [14]

Answer: Option C.

Step-by-step explanation:

A function goes trough the x-axis when f(x) = 0 for some value of x.

For example, when we say that a quadratic function has no real zeros, this means that the determinant is less than zero, so the roots of the equation:

a*x^2 + b*x + c = 0

are complex roots, this means that for the function:

f(x) = y = a*x^2 + b*x + c

there is not a real number x such f(x) = 0

So the correct option is C.

6 0
3 years ago
How do i solve <br> 3v + 1 + 7v = -12
riadik2000 [5.3K]

Answer:

-1.3

Step-by-step explanation:

3v+1+7v=-12 equation

10v+1=-12 combine like terms

10v=-13 subtract 1 from both sides

v=-1.3 divide by 10

4 0
2 years ago
Read 2 more answers
Third-degree, with zeros of -3,-1, and 2, and passes through the point (3,6).
Y_Kistochka [10]

Answer:

Below.

Step-by-step explanation:

In factor form this is:

f(x) = a(x + 3)(x + 1)(x - 2)     where a is a number to be found.

As it passes through (3, 6) we have:

6 = a(3 + 3)(3 + 1)(3 - 2)

24a = 6

a = 1/4.

So f(x) =  1/4(x + 3)(x + 1)(x - 2)

In general form this is:

f(x) = 1/4 x^3 + 1/2 x^2 - 5/4 x - 3/2

3 0
2 years ago
Bret works for a printing company. He buys 5 packs of card. Each pack of card costs £14.06 How much money does Bret pay in total
klasskru [66]
Multiply 5 and £14.06 to get £70.30 this is your answer
8 0
3 years ago
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