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2 years ago

Can you help me please? I need this ASAP

Mathematics

2 answers:

Ksivusya [100]2 years ago

8 0

The answer is top right and left

denpristay [2]2 years ago

6 0

Answer:

Top left and right

Step-by-step explanation:

simply multiply the first number of Y with X

Hope this helps

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How do you graph y=2/3x-4

Masja [62]

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▹ Answer

You can use a graphing calculator.

▹ Step-by-Step Explanation

Attached is a screenshot.

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8 0

4 years ago

Read 2 more answers

4 x 100 + 8 x 10 + 9 x 1 + 8 x (1/100) + 5 x (1/1,000) in standard form.

Phoenix [80]

What’s standard form again? I forgot

4 0

3 years ago

Plz gyz ineed the calculation

postnew [5]

Answer:

1/8

Step-by-step explanation:

1st day......1/3

2nd day....1/6

3rd day....3/8

common denominator of 24

1/3 + 1/6 + 3/8 = 8/24 + 4/24 + 9/24 = 21/24 (this is water used)

that means that : (24/24 - 21/24) = 3/24 reduces to 1/8 .....water in the tank

6 0

4 years ago

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

3 years ago

What is the prime factorization of 140? A 2^2×3×7 B. 2^3×7 C. 4×5×7 D. 2^2×5×7

Andreyy89

Answer:

Step-by-step explanation:

7 0

3 years ago