Answer:
i think its just the last one
Step-by-step explanation:
because the first two are all real numbers and the thrid equals one
What is the binomial raised to? you can’t do this problem without it
Answer:
y=2x-11
Step-by-step explanation:
Put it in the form y=mx+b=>y=2x-1/2. Instead of -1/2, put it as b, since you want it to go through 3,-5. y=2m+b when it goes through (3,-5) happens when -5=3*2-b. Do algebra, and get b as 11. That means the equation is y=2x-11.
Answer:
The sequence diverges.
Step-by-step explanation:
A sequence 
converges when 
is a real number.
In this question, the sequence given is:
The cosine is always going to be between -1 and 1, so for the convergence of the sequence, we look it as: 
. So
Since the limit is not a real number, the sequence diverges.
HG^2 = FG * (FG + EF)
Fill in the values:
(x+3)^2 = x * (7+x)
Simplify the right side:
(x+3)^2 = 7x +x^2
Rewrite the left side using the FOIL method
x^2 + 6x + 9 = 7x +x^2
Subtract x^2 from both sides:
6x +9 = 7x
Subtract 6x from both sides:
x = 9
Now you have x solve for HG
HG = x +3 = 9+3 = 12
The answer is A.
