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spayn [35]
3 years ago
9

Half-life of Po-210 is 140 days. If the initial mass of the sample is 5

Mathematics
1 answer:
Anna35 [415]3 years ago
4 0

Answer:

0.625kg

Step-by-step explanation:

we are given half-life of PO-210 and the initial mass

we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>

in order to solve so we can consider the half-life formula given by

\displaystyle f(t) = a {0.5}^{t/T}

where:

  • f(t) is the remaining quantity of a substance after time t has elapsed.
  • a is the initial quantity of this substance.
  • T is the half-life

since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5

thus substitute:

\displaystyle f(420)=5\cdot{0.5}^{420/140}

reduce fraction:

\displaystyle f(420)=5\cdot{0.5}^{3}

By using calculator we acquire:

\displaystyle f(420)=0.625

hence, the remaining sample after 420 days is 0.625 kg

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The half life of radium is 1690 years. if 80 grams are present now, how much will be present in 830 years
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Answer:

A(t) = amount remaining in t years

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Since A(1690) = (1/2)A0 and A0 = 80,

                we have 40 = 80e1690k

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Step-by-step explanation:

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