Half-life of Po-210 is 140 days. If the initial mass of the sample is 5
1 answer:
Answer:
Step-by-step explanation:
we are given half-life of PO-210 and the initial mass
we want to figure out the remaining mass <u>after</u><u> </u><u>4</u><u>2</u><u>0</u><u> </u><u>days</u><u> </u>
in order to solve so we can consider the half-life formula given by
where:
f(t) is the remaining quantity of a substance after time t has elapsed. a is the initial quantity of this substance. T is the half-life since it halves every 140 days our T is 140 and t is 420. as the initial mass of the sample is 5 our a is 5
thus substitute:
reduce fraction:
By using calculator we acquire:
hence, the remaining sample after 420 days is 0.625 kg
You might be interested in
Answer Is 0.5 Thank Me Later
Answer:
-60
Step-by-step explanation:
O g p r o b l e m : x(2x + 2x - 8y + 16)
S u b s t i t u t i o n : 3(6 + 6 - 48 + 16)
S o l v e : 3(12 - 48 + 16)
3(-36 + 16)
3(-20) = - 6 0
Answer:
B is your answer.
Step-by-step explanation:
Depends on 18/36 = 72/444, because 444 doesn't make sense at all. None of the others are equivalent. If it's 72/144 then this is the answer
Hope this helps.
Answer:
38
Step-by-step explanation:
Pemdas
P = Parentheses
E = Exponents
M = Multiplication
D = Division
A = Addition
S = Subtraction
Answer:
A manufacturer can save money by making a can that maximizes volume and minimizes the amount of metal used. For a can with radius r and height h, this goal is reached when 2πr³ = πr²h. Part A Solve the equation for h.
Step-by-step explanation: