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Wewaii [24]
2 years ago
11

Please help with the attached photo.

Mathematics
1 answer:
mina [271]2 years ago
7 0

The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²)  + 4x² = 1

<h3>What is an equation?</h3>

An equation is an expression that shows the relationship between two or more variables and numbers.

In polar form:

r = √(x² + y²) and cosФ = x / √(x² + y²)

Hence:

r(1 - 2cosФ) = 1

√(x² + y²) [1 - 2(x / √(x² + y²))] = 1

√(x² + y²) - 2x = 1

Take square of both sides:

x² + y² - 4x√(x² + y²)  + 4x² = 1

The solution to the equation r(1 - 2cosФ) = 1 is given as x² + y² - 4x√(x² + y²)  + 4x² = 1

Find out more on equation at: brainly.com/question/2972832

#SPJ1

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The cash drawer of the market contains $227. There are six more $5 bills than $10 bills. The number of $1 bills is two more than
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Answer:

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

Step-by-step explanation:

There are bills of one dollar, five dollars and ten dollars on the cash drawer, therefore the sum of all of them multiplied by their respective values must be equal to the total amount of money on the drawer. We will call the number of one dollar bills, five dollar bills and ten dollar bills, respectively "x","y" and "z", therefore we can create the following expression:

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We know that there are six more 5 dollar bills than 10 dollar bills and that the number of 1 dollar bills is two more than 24 times the number of 10 dollar bills, therefore:

y = z + 6\\x = 2 + 24*z

Applying these values on the first equation, we have:

2 + 24*z + 5*(z + 6) + 10*z = 227\\2 + 24*z + 5*z + 30 + 10*z = 227\\39*z + 32 = 227\\39*z = 227 - 32\\39*z = 195\\z = \frac{195}{39}\\z = 5

Applying z to the formulas of y and x, we have:

y = 5 + 6 = 11\\x = 2 + 24*5 = 122

There are 122 one dollar bills, 11 five dollar bills and 5 ten dollar bills.

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