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I am Lyosha [343]

2 years ago

6

Hao bought a 16-pound bag of dog food. If his dog eats pound of food every day, for how many days will the bag of dog food last?

2 answers:

kumpel [21]2 years ago

4 0

If it’s asking for if he eats 1 pound per day than 16 days

densk [106]2 years ago

3 0

Answer:

uh 1 pound per day 16 pounds so 16 days, i guess

Step-by-step explanation:

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How many days until christmas 3017 dec 25

devlian [24]

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3 years ago

1/4 (20x−28) <2(x−3)+2

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Answer:

Step-by-step explanation:

1/4 x 20x - 1/4 x 28<2x - 6 + 2

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2 years ago

A fish swims at a speed of 12 miles per hour. A boy swims at a speed of 4.4 feet per second. 3 ft = 1 yd 5280 ft = 1 mi How much

just olya [345]

You'll need to convert both speeds into yards per minute.

12 mph = 12 mph 1760 yd 60 min
---------- * ------------ * ----------
1 mile 1 hr

Note that "miles" cancels. So does "hours." Finish this work.

Then convert 4.4 ft/sec into yards per minute.

Then, finally, compare your two rates via subtraction of the smaller from the larger.

4 0

3 years ago

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Fifty-three percent of employees make judgements about their co-workers based on the cleanliness of their desk. You randomly sel

GarryVolchara [31]

Answer:

The unusual $X$ values for this model are: $X = 0, 1, 2, 7, 8$

Step-by-step explanation:

A binomial random variable $X$ represents the number of successes obtained in a repetition of $n$ Bernoulli-type trials with probability of success $p$ . In this particular case, $n = 8$ , and $p = 0.53$ , therefore, the model is ${8 \choose x} (0.53) ^ {x} (0.47)^{(8-x)}$ . So, you have:

$P (X = 0) = {8 \choose 0} (0.53) ^ {0} (0.47) ^ {8} = 0.0024$

$P (X = 1) = {8 \choose 1} (0.53) ^ {1} (0.47) ^ {7} = 0.0215$

$P (X = 2) = {8 \choose 2} (0.53)^2 (0.47)^6 = 0.0848$

$P (X = 3) = {8 \choose 3} (0.53) ^ {3} (0.47)^5 = 0.1912$

$P (X = 4) = {8 \choose 4} (0.53) ^ {4} (0.47)^4} = 0.2695$

$P (X = 5) = {8 \choose 5} (0.53) ^ {5} (0.47)^3 = 0.2431$

$P (X = 6) = {8 \choose 6} (0.53) ^ {6} (0.47)^2 = 0.1371$

$P (X = 7) = {8 \choose 7} (0.53) ^ {7} (0.47)^ {1} = 0.0442$

$P (X = 8) = {8 \choose 8} (0.53)^{8} (0.47)^{0} = 0.0062$

The unusual $X$ values for this model are: $X = 0, 1, 7, 8$

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How to make 7,502 only using hundreds , tens , and ones

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14 hundreds, 10 tens, and 2 ones.

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