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slega [8]
1 year ago
6

George is building a fence around a rectangular dog run. He is using his house as one side of the run. The area of the dog run w

ill be 240 square feet. The length of the run is 30 feet, and the width is (30 minus x) feet. The diagram below shows his plan.
Recall the formulas for area and perimeter: A = lw and P = 2l + 2w.


A rectangle labeled Dog run has a length of 30 feet and width of (30 minus x) feet.

How many feet of fencing will George need for the dog run?
Mathematics
1 answer:
pav-90 [236]1 year ago
8 0

Answer:

width is 30-22 = 8 feet

George would need 76 feet of fencing for the dog run

Step-by-step explanation:

30 x (30-x) = 240

30-x = 8

-x = -22

x = 22

Therefore width is 30-22 = 8 feet

8+8+30+30 = 76

Thus, George would need 76 feet of fencing for the dog run

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option-B......Answer

Step-by-step explanation:

We are given

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now, we can use formula

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we can plug values

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Find the simple interest on Rs. 4500 for 6 months at
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2 years ago
4x+y=14, 6x-3y=3 is the question​
fomenos

Answer:

if you are being asked what the values of the x and y variables are, x=5/2 and y=4

Step-by-step explanation:

In order to solve this problem you will want to isolate one of the two variables in both equations.

I isolated the y variable in both equations so you have:

4x+y=14, when you isolate the y variable, you will get: y=-4x+14

6x-3y=3, same procedure isolate y: 6x-3=3y, now simplify so you only have y: 2x-1=y.

Now that you have the two equations which a common variable, solve them by making the two equations equal to each other like so:

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2 years ago
An 11-inch by 8-inch piece of cardboard has squares cut out of the corners and is folded up to make an open-top box. If the volu
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Option D

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