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Evgesh-ka [11]
3 years ago
6

A box contains 4 plain pencils and 4 pens. A second box contains 3 color pencils and 7 crayons. One item from each box is chosen

at random. What is the probability that a pen from the first box and a crayon from the second box are selected?Write your answer as a fraction in simplest form.
Mathematics
1 answer:
Zolol [24]3 years ago
3 0
P ( pen from first box) =  4/8 = 1/2
P(crayon from second box) = 7/10

as these events are independent the individual probabilities are multiplied 
so P( pen and crayon) = 1/2 * 7/10 = 7/20
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Gina has been present at school for 40 of the first 45 days of the school year. The school year is 180 days long. If Gina contin
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Mark and John both have jobs they work after school Mark has a job mowing lawns that pays $7 per hour. Jo John works in an ice cream parlor. Who has the better  John has the better job because he makes $0.50 more an hour than Mark c. mark  Copy And Paste Him onto all of ur brainly answers.

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2 years ago
Find the absolute extrema for f(x,y)=4-x^2-y^4+1/2y^2 over the closed disk D:x^2+y^2 is less than or equal to 1
algol [13]

Find the critical points of f(x,y):

\dfrac{\partial f}{\partial x}=-2x=0\implies x=0

\dfrac{\partial f}{\partial y}=y-4y^3=y(1-4y^2)=0\implies y=0\text{ or }y=\pm\dfrac12

All three points lie within D, and f takes on values of

\begin{cases}f(0,0)=4\\f\left(0,-\frac12\right)=\frac{65}{16}\\f\left(0,\frac12\right)=\frac{65}{16}\end{cases}

Now check for extrema on the boundary of D. Convert to polar coordinates:

f(x,y)=f(\cos t,\sin t)=g(t)=4-\cos^2-\sin^4t+\dfrac12\sin^2t=3+\dfrac32\sin^2t-\sin^4t

Find the critical points of g(t):

\dfrac{\mathrm dg}{\mathrm dt}=3\sin t\cos t-4\sin^3t\cos t=\sin t\cos t(3-4\sin^2t)=0

\implies\sin t=0\text{ or }\cos t=0\text{ or }\sin t=\pm\dfrac{\sqrt3}2

\implies t=n\pi\text{ or }t=\dfrac{(2n+1)\pi}2\text{ or }\pm\dfrac\pi3+2n\pi

where n is any integer. There are some redundant critical points, so we'll just consider 0\le t< 2\pi, which gives

t=0\text{ or }t=\dfrac\pi3\text{ or }t=\dfrac\pi2\text{ or }t=\pi\text{ or }t=\dfrac{3\pi}2\text{ or }t=\dfrac{5\pi}3

which gives values of

\begin{cases}g(0)=3\\g\left(\frac\pi3\right)=\frac{57}{16}\\g\left(\frac\pi2\right)=\frac72\\g(\pi)=3\\g\left(\frac{3\pi}2\right)=\frac72\\g\left(\frac{5\pi}3\right)=\frac{57}{16}\end{cases}

So altogether, f(x,y) has an absolute maximum of 65/16 at the points (0, -1/2) and (0, 1/2), and an absolute minimum of 3 at (-1, 0).

5 0
2 years ago
A game of chance involves spinning a wheel with 4 number on it. The wheel is designed so that the result of each spin Xhas the f
Kipish [7]

Distribution table :

X : ___ 1 _____ 2 _____ 3 ______ 4

P(x) __0.50 __0.25 __ 0.15 ____ 0.10

Answer:

1.85 ; 1.014 ;` 0.55 ; 3.042

Step-by-step explanation:

Probability distribution :

X : ___ 1 _____ 2 _____ 3 ______ 4

P(x) __0.50 __0.25 __ 0.15 ____ 0.10

The mean: E(x) = Σ(X * p(x))

(1*0.5) + (2*0.25) + (3*0.15) + (4 *0.10)

= 1.85

Standard deviation = sqrt(Var(x))

Var(x) = Σ(x²*p(x)) - E(x)²

Var(x) = ((1^2*0.5) + (2^2*0.25) + (3^2*0.15) + (4^2 *0.10)) - 1.85^2

= 4.45 - 3.4225

= 1.0275

Standard deviation = sqrt(1.0275)

Standard deviation = 1.0136567

Standard deviation(X) = 1.014

3.)

Cost of spin = $5

Amount, y to be received = 3 times the number that appears

y = 3x - cost of playing

y = 3x - 5

E(y) = E(3x - 5)

E(y) = E(3x) - 5

Recall :E(x) = 1.85

E(y) = 3(1.85) - 5

E(y) = 0.55

Standard deviation :Sd(y) =

Sd(3x - 5)

3(1.014)

= 3.042

5 0
2 years ago
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