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tatyana61 [14]
2 years ago
13

I'm kinda lost in this problem. Can you teach me how to solve these ​

Mathematics
1 answer:
boyakko [2]2 years ago
8 0

53) Vertical angles are congruent, so m\angle IDA=121^{\circ}

54) \angle YDA and \angle YDF are supplementary, so m\angle YDA=180^{\circ}-121^{\circ}=59^{\circ}

55) Because vertical angles are congruent, m\angle FDI=59^{\circ}. Now, because DR bisects \angle FDI, this means m\angle RDI=\frac{59}{2}=29.5^{\circ}

56) This is a geometric sequence where the next term is obtained by multiplying the previous term by -2, so the next two numbers are 16, -32

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Metal strips 11 feet long and 2 feet wide . of the stripping costs $6 per foot , find the total costs
adoni [48]
The area of the metal strips:
A = L * W , where L stays for length and W stays for wirth.
A = 11 ft * 2 ft ;
A = 22 ft^2.
If it costs $6 per foot:
Total cost = 22 * 6 = $132.
Answer: The total cost of a metal strip is $132.
5 0
3 years ago
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I’m struggling on this one
NemiM [27]

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3 years ago
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Setler [38]

Answer:-5

Step-by-step explanation:

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3 years ago
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Simplify square root of ten times square root of eight.
Romashka-Z-Leto [24]
<h2>Explanation:</h2><h2></h2>

Here we need to simplify the square root of ten times square root of eight, so let's write this step by step:

Step 1. The square root of ten

\sqrt{10}

Step 2. The  square root of eight

\sqrt{8}

Step 3. The square root of ten times square root of eight

\sqrt{10}\times \sqrt{8} \\ \\ \\ \text{From radical property:} \\ \\ \sqrt{a}\times \sqrt{b}=\sqrt{ab} \\ \\ \\ So: \\ \\ \sqrt{10}\times \sqrt{8}=\sqrt{80} \\ \\ \\ But: \\ \\ \sqrt{80}=\sqrt{16\time5}=\sqrt{16}\sqrt{5}=4\sqrt{5}

Finally, the correct option is:

<em>Four square root of five</em>

4 0
3 years ago
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1.what is the sum or difference? 3x^8-7x^8<br>A.-4x^16<br>B. -21x^8<br>C. -4x^8<br>D. 10x^-8
Dafna1 [17]
To simplify the given equation, you want to combine like terms. Since both terms have x^8, we can add the coefficients and leave the x^8
3x^8-7x^8 (do 3-7)
=-4x^8 so the answer is C

Hope this helps
5 0
3 years ago
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