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OlgaM077 [116]
2 years ago
15

What type of function is this?​

Mathematics
2 answers:
scZoUnD [109]2 years ago
8 0
It is a sech x function
Paraphin [41]2 years ago
5 0

Answer:

It's a sech x function

Step-by-step explanation:

Explanation is in attached file

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Need help with this problem. ​
tigry1 [53]

Answer:

C) -\frac{47}{49}

Step-by-step explanation:

By the cos double angle formula, we know \cos(2\theta)=2\cos^2\theta-1. Substituting \cos \theta into the formula, we get

\cos(2\theta)=2(-\frac{1}{7})^2-1\\~~~~~~~~~~=\frac{2}{49}-1\\~~~~~~~~~~=\boxed{-\frac{47}{49}}.

The answer is C.

5 0
2 years ago
What is 420 centimeters to meter
Ronch [10]

Here is the best answerrrrr.

8 0
4 years ago
Read 2 more answers
18) What value of x makes R(x) = 10
Illusion [34]
<h3>Two Answers:  <u>x = 2 and x = 10</u></h3>

========================================================

Explanation:

Draw a horizontal line through 10 on the y axis. This is because R(x) = 10 is the same as y = 10. The output of the function is the y value.

See the diagram below.

The horizontal line crosses the parabola at two locations. From those points, draw a vertical line straight down to the x axis. Note how we land at x = 2 and x = 10. This means that R(2) = 10 and R(10) = 10.

8 0
3 years ago
How will you remember what changes when reflecting across the x-axis?
natulia [17]

Answer: When you reflect a point across the x-axis the x-coordinate remains the same, but the y-coordinate is transformed into its opposite

Step-by-step explanation:

5 0
3 years ago
0/1 For positive integer n, n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?. What is the value of 4# · 3# · 2# · 1#?
MakcuM [25]

Answer:

331776

Step-by-step explanation:

Since n? = n! · (n − 1)! · … · 1! And n# = n? · (n − 1)? · … · 1?

Then 4# = 4? · (4 − 1)? · (4 − 2)?· 1?

= 4? · 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 4? = 4! · (4 − 1)! · (4 − 2)! · 1! = 4! · 3! · 2! · 1! = 288

Thus, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Also, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 4# = 4? · 3? · 2?· 1? = 288 × 12 × 2 × 1 = 6912

We now find 3#

3# = 3? · (3 − 1)? · 1? = 3? · 2?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 3? = 3! · (3 − 1)! · 1! = 3! · 2! · 1! = 12

Thus, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

and, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 3# = 3? · 2?· 1? = 12 × 2 × 1 = 24

We now find 2#

2# = 2? · (2 − 1)? · 1? = 2? · 1?· 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 2? = 2! · (2 − 1)! · 1! = 2! · 1! · 1! = 2

1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

So, 2# = 2?· 1? = 2 × 1 = 2

We now find 1#

1# = 1? · 1? = 1? · 1?

Now, n? = n! · (n − 1)! · … · 1!

So, 1? = 1! · (1 − 1)! · 1! = 1! · 0! · 1! = 1

And, 1# = 1? · 1? = 1 × 1 = 1

So,  4# · 3# · 2# · 1#? =  6912 · 24 · 2 · 1? = 331776

7 0
3 years ago
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